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Anastaziya [24]
1 year ago
6

A 75.0-liter canister contains 15.82 moles of argon at a pressure of 546.8 kilopascals. what is the temperature of the canister?

the temperature of the canister is k.
Chemistry
1 answer:
Eduardwww [97]1 year ago
7 0

The temperature of the canister is 311.82(OR 312)K

Given:

volume of canister = 75.0-liter

moles of argon = 15.82 moles

pressure = 546.8 kilopascals

To Find:

temperature of the canister

Solution: Pressure of argon = 546.8 kPa

Conversion factor: 1 atm = 101.325 kPa

According to Ideal gas law,

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature

T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol-¹K-¹)

T = 311.82 K

Hence the temperature of the canister is 311.82 K.

Learn more about Temperature here:

brainly.com/question/25677592

#SPJ4

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