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3 years ago

Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of

Physics

1 answer:

VladimirAG [237]3 years ago

6 0

Answer:

4.9612 s

Explanation:

Applying,

T = 2π√(L/g)............... Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

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Air enters an adiabatic compressor at 104 kPa and 292 K and exits at a temperature of 565 K. Determine the power (kW) for the co

ladessa [460]

Answer:

$\dot W_{in} = 49.386\,kW$

Explanation:

An adiabatic compressor is modelled as follows by using the First Law of Thermodynamics:

$\dot W_{in} + \dot m \cdot c_{p}\cdot (T_{1}-T_{2}) = 0$

The power consumed by the compressor can be calculated by the following expression:

$\dot W_{in} = \dot m \cdot c_{v}\cdot (T_{2}-T_{1})$

Let consider that air behaves ideally. The density of air at inlet is:

$P\cdot V = n\cdot R_{u}\cdot T$

$P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T$

$\rho = \frac{P\cdot M}{R_{u}\cdot T}$

$\rho = \frac{(104\,kPa)\cdot (28.02\,\frac{kg}{kmol})}{(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} )\cdot (292\,K)}$

$\rho = 1.2\,\frac{kg}{m^{3}}$

The mass flow through compressor is:

$\dot m = \rho \cdot \dot V$

$\dot m = (1.2\,\frac{kg}{m^{3}})\cdot (0.15\,\frac{m^{3}}{s} )$

$\dot m = 0.18\,\frac{kg}{s}$

The work input is:

$\dot W_{in} = (0.18\,\frac{kg}{s} )\cdot (1.005\,\frac{kJ}{kg\cdot K})\cdot (565\,K-292\,K)$

$\dot W_{in} = 49.386\,kW$

5 0

3 years ago

Why are planets closer to the sun made of different substance than planets father from the sun?

MA_775_DIABLO [31]

I think the answer would be c

7 0

4 years ago

A ball rolls 50 meters in

-Dominant- [34]

The speed of the ball is B. 5 meters per second

Explanation:

For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation

$v=\frac{d}{t}$

where

v is the speed

d is the distance covered

t is the time taken

For the ball in this problem:

d = 50 m is the distance covered

t = 10 s is the time taken

Substituting, we find the speed:

$v=\frac{50}{10}=5 m/s$

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

3 0

3 years ago

If a waves frequency is 4Hz, and its wavelength is 5 m, then what is its speed?

hammer [34]

Answer:

speed = 20 m/s

Explanation:

speed = frequency * wavelength

speed = 4 * 5

speed = 20 m/s

6 0

3 years ago

A 200 g, 20 cm diameter plastic disk is spun on an axle through its center by an electric motor. What torque must the motor supp

Rama09 [41]

Answer: The torque required is 0.0471 N m.

Explanation:

Mass of the disc = 200 g = 0.2 kg (1 kg =1000 g)

Radius of the disc = $\frac{Diameter}{2}$ = 10 cm = 0.1 m(1 m = 100 cm)

Angular acceleration = $\alpha$

$\alpha =\frac{2\pi\times 1800}{60 \times 4 sec}=15\pi rad/s^2$

Moment of inertia = $\frac{1}{2}\times mass\times (radius)^2=\frac{1}{2}\times0.2 kg\times (0.1 m)^2=0.001 kg m^2$

$Torque=\alpha \times I=0.001 kg m^2\times 15\times 3.14 rad/s^2r=0.0471 N m$

The torque required is 0.0471 N m.

7 0

4 years ago