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3 years ago

Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of

Physics

1 answer:

VladimirAG [237]3 years ago

6 0

Answer:

4.9612 s

Explanation:

Applying,

T = 2π√(L/g)............... Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

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A ball thrown straight up takes 1.89s to reach a height of 41.6m.

yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

8 0

2 years ago

What happens when an object is dropped? A. It decelerates at a rate of 9.8 m/s/s. B. It travels 9.8 meters before stopping. C. I

andreev551 [17]

I think its c I really don't take physics but I try to help.

5 0

2 years ago

You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l

sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

We will use the second equation of motion to find out the initial speed of the arrow.

$h= v_it + \frac{1}{2}gt^2\\$

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}$

vi = 9.81 m/s

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

$h= v_it + \frac{1}{2}gt^2\\$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

$17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0$

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

t = 1.13 s

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0

1 year ago

A drop of oil of volume 10m it spread out on water to make a circular firm of radius 10m calculate the tickness of the firm

Effectus [21]

Answer:

h = 3.1 cm

Explanation:

Given that,

The volume of a oil drop, V = 10 m

Radius, r = 10 m

We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :

$V=\pi r^2 h\\\\h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10}{\pi \times 10^2}\\\\h=0.031\ m\\\\h=3.1\ cm$

So, the thickness of the film is equal to 3.1 cm.

8 0

2 years ago

A satellite s is moving in an elliptical orbit around the earth . the mass of satellite is very small compared to mass of earth.

Contact [7]

The best and most correct answer among the choices provided by your question is the second choice or letter B.

A satellite (s) is moving in an elliptical orbit around the earth has its angular momentum towards the earth changing in direction, but not in magnitude.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

8 0

3 years ago