The pairs of angles<span> on opposite sides of the transversal but outside the two lines are called </span>alternate exterior angles<span>.
</span><span>C) Because they are alternate exterior angles.</span>
Answer:
3/8 π radians
Step-by-step explanation:
The Area of a sector when then central angle is in radians = 1/2r² θ
Where
θ = central angle = ?
r = 16 cm
Area of the sector = 48πcm²
Hence
Central angle = Area of a sector ÷ (1/2r²)
= 48πcm² ÷ (1/2 × 16²)
= 48πcm² ÷ 128
Central angle = 3/8π radians
Therefore, Central angle = 3/8π radians
9 x ≥ 117
Divide both sides by 9 :
9 x / 9 ≥ 117 / 9
x = 117 / 9
x ≥ 13
hope this helps!
It should be "A"
On the number line, it shows that -4.5 is further and to the right of -2.3.
Hope that helps!
Answer:
Step-by-step explanation:
(27)^(-1/3) + (32)^(-2/5)
1/3 + 1/4
4/12 + 3/12 = 7/12
