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3 years ago

Which expressions are equivalent to the one below?? 36^x/6^x

Mathematics

2 answers:

Keith_Richards [23]3 years ago

5 0

It would be six because they are like terms.

Alex787 [66]3 years ago

3 0

6^x*6^x/6^x

(36/6)^x

6^x

all these are equivalent

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Ms. Martinez bought 36-pint sized containers of strawberry yogurt. How many gallons is that?

BabaBlast [244]

Answer:

4.5 gallons

Step-by-step explanation:

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2 years ago

Convert the following equation to slope-intercept form y+5=1/2(x-8)

alexandr402 [8]

Answer: y = 1/2x - 9

Step-by-step explanation:

y + 5 = 1/2(x - 8)
y + 5 = 1/2x - 4 (distribute)
y = 1/2x - 9 (subtract 5 from both sides)

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2 years ago

A. The following events are mutually exclusive: Living in California and watching American Idol. True or False b. The number of

BlackZzzverrR [31]

Answer:

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3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago

Simplify, brainliest to the most elaborated answer.

xxTIMURxx [149]

Answer:

wait writing on a piece of paper

6 0

3 years ago