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BlackZzzverrR [31]
4 years ago
12

SOS PLEASE HELP 30 POINTS WILL GIVE BRAINLIEST The isosceles trapezoids, ABCD and EFGH, are similar quadrilaterals. The scale fa

ctor between the trapezoids is 2:3, = 6 centimeters, = 8 centimeters, and is three times the length of . Use complete sentences to answer the following prompts and include all of your calculations in your final answer.
Write a similarity statement for each of the four pair of corresponding sides.
Write a congruence statement for each of the four pair of corresponding angles.
Determine the perimeter for each of the isosceles trapezoids
Mathematics
1 answer:
m_a_m_a [10]4 years ago
4 0
Answer: Answer Number 1; Line AB is similar to
line EF
Line BC is similar to line FG
Line CD is similar to line GH
Line DA is similar to line HE
Step-by-step explanation: First and foremost both
quadrilaterals are similar but of varying dimensions.
If we label both trapezoids as ABCD and EFGH
respectively, then it follows that the corresponding
lines (as stated in the answer above) would also be
similar.
Same applies to the four angles in the interior of the
trapezoids.
Number 2, Angle A equals Angle E
Angle B equals Angle F
Angle C equals Angle G
Angle D equals Angle H
Number 3,
If the scale factor between both figures is 2:3, then
for every length of a side in figure ABCD, the
corresponding side in figure EFGH would be
multiplied by 3/2.
Therefore if AD is 8cm, then EH equals 8 x 3/2
That gives us 12cm.
If GH is 6cm, then DC equals 6 x 2/3. That gives
us 4cm.
If AB is 3 times the length of DC, then AB equals 3
x 4, that gives us 12cm.
If AB is 12cm, then EF equals 12 x 3/2. That gives
us 18cm.
Take note that the shapes are both isosceles
trapezoids, o we have two sides of equal length, AD
and BC in the first figure and then EH and FG in the
other figure.
The first trapezoid has sides 8cm, 12cm, 8cm and
4cm. The perimeter is given as 8+12+8+4 32cm.
The second trapezoid has sides 12cm, 18cm, 12cm
and 6cm. The perimeter is given as 12+18+12+6=
48cm.
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What is the 17th term in the arithmetic sequence in which a6 is 101 and a9 is 83
monitta

Answer:

The 17th term in arithmetic sequence is 68

Step-by-step explanation:

The general formula of arithmetic sequence is:

aₙ = a₁ + (n – 1)d.

We are given a₆ = 101 and a₉ = 83 and we need to find a₁₇

To find the term a₁₇ we should know a₁ and d. So we would find both

a₆ = a₁ +(6-1)d

101 = a₁ +(5)d

101 = a₁ +5d     eq(1)

and

a₉ = a₁ +(9-1)d    

83 = a₁ + 8d       eq(2)

Subtracting eq(2) from eq(1)

101 = a₁ +5d

83 = a₁ + 8d

-       -     -

__________

18 = -3d

=> d = 18/-3

=> d = -6

Putting value of d in eq(1)

101 = a₁ + 5d

101 = a₁ + 5(-3)

101 = a₁ -15

=> a₁ = 101+15

=> a₁ = 116

Now finding a₁₇:

aₙ = a₁ + (n – 1)d.

a₁₇ = 116 +(17-1)(-3)

a₁₇ = 116+(16)(-3)

a₁₇ = 116 - 48

a₁₇ = 68

So, the 17th term in arithmetic sequence is 68

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