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Dafna1 [17]
3 years ago
10

There are two containers: one container with a 0.15 molar solution of compound A and another with 0.20 molar solution of compoun

d B. What is true about these two containers
Chemistry
1 answer:
Margaret [11]3 years ago
6 0

Answer:

The container that has 0.20 moles of the compound has more moles compared to the container that has 0.15 moles of compound A

Explanation:

The molarity is defined as the concentration of a substance in solution, expressed as the number of moles of a solute per liter of solution.

From the given information.

In compound A

Molarity of the solution = 0.15 molar = 0.15 m/L

It implies that, In compound A, there are 0.15 moles present in 1 L of the solution.

Similarly;

In compound B

Molarity of the solution = 0.20 molar = 0.20 m/L

It implies that, In compound B, there are 0.120 moles present in 1 L of the solution.

Thus, we can conclude that:

The container that has 0.20 moles of the compound has more moles compared to the container that has 0.15 moles of compound A

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22. Radon has a half-life of 3.83 days. How long will it take a 225 g sample to decay to 14.06 g? (3pts.)
prohojiy [21]

Answer:

15.32 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 3.83 days

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Time (t) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Number of half-lives (n) =?

N = N₀ / 2ⁿ

14.06 = 225 / 2ⁿ

Cross multiply

14.06 × 2ⁿ = 225

Divide both side by 14.06

2ⁿ = 225 / 14.06

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 3.83 days

Number of half-lives (n) = 4

Time (t) =.?

n = t / t½

4 = t / 3.83

Cross multiply

t = 4 × 3.83

t = 15.32 days

Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days

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