All categories

2 years ago

Please solve ...................................................................

Chemistry

1 answer:

scZoUnD [109]2 years ago

7 0

Answer:

Explanation:

Part (c)

Mix together two suitable solutions.

Use filtration to separate the precipitate as a residue from the solution.

Wash the precipitate with distilled water while it is in the filter funnel.

Leave the washed precipitate aside or in a warm oven to dry.

Part (d)

Pb(NO3)2 (aq) + Na2SO4 (aq) → 2 NaNO3 (aq) + PbSO4 (s)

You might be interested in

Name the following cycloalkane:

KonstantinChe [14]

B is the correct answer

8 0

3 years ago

What effect did the Punic Wars have on Rome's military development? (4 points)

Doss [256]

Answer:

The correct answer is: “The Roman army grew in size and became dominant in the Mediterranean region”.

Explanation:

The Punic wars were a series of three wars that were fought between Rome and Carthage. At the end of the third war, Rome established itself as an empire, it conquered the Carthage’s empire, destroyed it completely and became the most powerful state of the Western Mediterranean.

6 0

3 years ago

How long does it take to get into ketosis?

WITCHER [35]

2 days. 20 grams of carbohydrates

5 0

3 years ago

Select all of the following that are physical changes A. turning a tin can into aluminum foil B. breaking a window into very tin

Ede4ka [16]

Answer:

A, B, E

Explanation:

thats just how it works

5 0

3 years ago

Milk of magnesia is often taken to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 te

Igoryamba

Answer:

8.61 mL of the HCl solution

Explanation:

The reaction that takes place is:

2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:

4x10² mg = 400 mg = 0.400g

0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂

6.859*10⁻³ mol Mg(OH)₂ * $\frac{1molHCl}{1molMg(OH)_{2}} =$ 3.429x10⁻³ mol HCl

Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:

pH = -log[H⁺]

1.4 = -log[H⁺]

$10^{-1.4}$ = [H⁺]

0.0398 M = [H⁺] = [HCl] *Because HCl is a strong acid*

Thus, the volume is:

0.0398 M = 3.429x10⁻³mol HCl / Volume

Volume = 8.616x10⁻³ L = 8.62 mL

6 0

3 years ago

Read 2 more answers