The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
<h3>
What is the amount of Amoxicillin dose given to the child?</h3>
The amount of Amoxicillin dose given to the child is calculated as follows;
amount of Amoxicillin dose = weight of the child x dosage prescribed
<h3>What is the weight of the child in pounds (lb) </h3>
The weight of the child in pounds (lb) is calculated as follows;
1 lb = 0.453592 kg
85.4 lb = ?
= 85.4 x 0.453592 kg
= 38.74 kg
amount of Amoxicillin dose = 38.74 kg x 45 mg/kg
amount of Amoxicillin dose = 1,743.3 mg
Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
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The complete question is below:
A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.
Answer:
100%
Explanation:
If all labels in the square are “t” then there is no way that the plants will not be tall. Therefore there is a 100% chance the plant will be tall.
To solve for moles use molar and volume:
M = mol/L
0.02700 m= mol/(.75 L)
mol = .036 mol of Hg(NO3)2
The proportion of Hg(NO3)2 to the Mercury that is used to create
HgS is 1:1 so solve for the moles of Mercury used. So:
.036 * (1 Hg(NO3)2 / 1 Hg) = .036 moles of Hg used to make
HgS
The proportion of Mercury to HgS is 1:1, as an alternative
of doing the obvious math you can conclude that .036 moles of HgS will be
produced because you're given .036 moles of Hg and an excess of S. Use the
molar mass of HgS to determine how many grams will be produced.
.036 moles * 232.66 g/mol = 8.37576 grams of Vermilion is
produced.
The d subshell has 5 orbitals (with each being able to hold two electrons. As such, the d orbital can hold a maximum of 10 electrons.
<span>The "d" subshell can hold a maximum of _TEN_ electrons.</span>
