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Olin [163]
2 years ago
11

When I cut it a gas will irritate my eye. Sometimes when I'm cooking you might see me cry.

Chemistry
1 answer:
Elena-2011 [213]2 years ago
3 0
Lol, onions. Onions produce a chemical irritant called synpropanerhial-S-oxide.
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In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 18.0°C. You identified that the ideal pressure (
Natasha2012 [34]

Answer:

4,38%

small molecular volumes

Decrease

Explanation:

The percent difference between the ideal and real gas is:

(47,8atm - 45,7 atm) / 47,8 atm × 100 = 4,39% ≈ <em>4,38%</em>

This difference is considered significant, and is best explained because argon atoms have relatively <em>small molecular volumes. </em>That produce an increasing in intermolecular forces deviating the system of ideal gas behavior.

Therefore, an increasing in volume will produce an ideal gas behavior. Thus:

If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to <em>decrease</em>

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I hope it helps!

5 0
3 years ago
Solutions are said to be what kind of mixture? A) Pure substance B) Heterogeneous C) Homogenous D) Element
laiz [17]
Solutions are said to be C. homogeneous mixtures, composed of two or more substances. It is usually liquid, however it may be solid or gas.
7 0
3 years ago
Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance
GrogVix [38]

Answer:

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Explanation:

We are given that  a reaction in which C_3H_8O_2 reacts with KMnO_4

We have to find the coefficient of each reactants in balanced reaction

3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O

Coefficient is defined the constant  value multiplied with a reactant in a reaction.

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Coefficient of C_3H_2O_4K_2=3

Coefficient of MnO_2=8

Coefficient of H_2O=8

Coefficient of KOH=2

Hence, Coefficient of C_3H_8O_2=3 and coefficient of KMnO_4=8

7 0
3 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
2 years ago
What is SEAgel help plz
DanielleElmas [232]

SEAgel (Safe Emulsion Agar gel) is one of a class of high-tech foam materials known as aerogels.

5 0
2 years ago
Read 2 more answers
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