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Zolol [24]
3 years ago
12

The Society of Automotive Engineers has established an accepted numerical scale to measure the viscosity of motor oil. For examp

le, SAE 40 motor oil has a higher viscosity than an SAE 10 oil. Rank the following hydrocarbons by their expected viscosity.
CH3CH2CH2CH2CH3
CH3(CH2)8CH3
CH3(CH2)11CH3
Chemistry
2 answers:
Sphinxa [80]3 years ago
6 0

Answer:

CH3(CH2)11CH3 > CH3(CH2)8CH3 > CH3CH2CH2CH2CH3

Explanation:

KengaRu [80]3 years ago
6 0

Answer:

CH3CH2CH2CH2CH3.

CH3(CH2)8CH3.

CH3(CH2)11CH3.

Explanation:

Viscosity is a material property which describes the resistance of a fluid to shearing flows. It corresponds roughly to the intuitive notion of a fluid's thickness. For instance, honey has a much higher viscosity than

water .

Viscosity is measured using a

viscometer . Measured values span several orders of magnitude. Of all fluids, gases have the lowest viscosities, and thick liquids have the highest.

The aforementioned hydrocarbon are has different viscosity and so are arrange in order of their viscosity.

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A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ
deff fn [24]

The empirical formula of the oxide is Co₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

 Cobalt + oxygen ⟶ cobalt oxide

29.05 g +    x g    ⟶     40.88 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + <em>x</em> g ⟶ 40.88 g

<em>x</em> = 40.88 – 29.05 = 11.83

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

<em>Moles of Co</em> = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

<em>Moles of </em>O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

<em>Step 4</em>. Multiply each number by a factor that makes the <em>ratio close to whole numbers </em>

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Co₂O₃

4 0
3 years ago
Please help I will give brainliest!
aleksklad [387]
I believe it’s the 3rd option
6 0
2 years ago
How many significant figures are in $10,000,210<br> 7<br> 3
nevsk [136]

Answer:

7

Explanation:

7 0
3 years ago
Read 2 more answers
If one mole of na3po4·3h2o is heated extensively, how many moles of water are released?
Aleks04 [339]

When one mole of Na3PO4.3H2O is heated extensively, three moles of water are released.

The water molecules in Na3PO4.3H2O are called molecules of water of crystallization. These molecules are not covalently bonded to the Na3PO4 molecule. They are only loosely attached to the substance.

Strong heating will drive away these molecules of water of crystallization to give three moles of water in the product.

Hence, when one mole of Na3PO4.3H2O is heated extensively, three moles of water are released.

Learn more: brainly.com/question/14252791

4 0
2 years ago
Mg + 2HCl ⟶ MgCl2 + H2
Ivanshal [37]

Answer: m = 24.31 g/mol · 1.13 mol

Explanation: 2 mol HCl use 1 mol Mg.

Magnesium is used 0.5 · 2.26 mol = 1.13 mol

M(Mg) = 24.31 g/ mol

7 0
2 years ago
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