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2 years ago

How many liters will 2.76 mol CO2 occupy? 2.76 mol II

1 answer:

6 0

This problem is providing information about the moles of carbon dioxide, 2.76 mol, and asks for the volume this amount takes up, turning out to be 61.8 L according to the Avogadro's law:

<h3>Avogadro's law:</h3><h3 />

In chemistry, gas laws are used to relate the behavior of gases by virtue of the their pressure, volume, temperature and moles; thus several gas laws exist for us to do so, however, we here focus on the Avogadro's law which relates the volume and moles when both temperature and pressure are held constant.

In such a way, since no information on the constant variables is given, we assume the mentioned carbon dioxide is at STP, (0 °C and 1 atm), which means that we can use the following equivalence statement derived from the ideal gas law (PV=nRT):

22.4 L = 1 mol

Hence, we calculate the required volume:

$2.76molCO_2*\frac{22.4L\ CO_2}{1molCO_2} =61.8L\ CO_2$

Learn more about ideal gases: brainly.com/question/11676583

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Which three temperature readings all mean the same thing?

allochka39001 [22]

Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Explanation:

Conversion of degree Celsius to Kelvin :

K=^oC+273

Conversion of degree Celsius to degrees Fahrenheit :

^oF=(\frac{9}{5}\times ^oC)+32

By using these two conversion factors, we get the three temperature readings all mean the same thing.

For option A :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option B :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option C :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

For option D :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

From the given options, only option (D) is correct.

Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

Hope this helps!

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3 years ago

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Density is the amount of mass found in a given space. Which statements are true about mass and/or density?

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A marble has more density than an inflated balloon.

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Match each element to the number of electrons in its valence shell

blondinia [14]

Answer: Be= 2, C =4, Li = 1 and B=3

Explanation:

The valence shell can be define as the outermost shell of an atom that contains the valence electrons.

Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.

Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.

Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.

Boron (B) , electronic configuration; 1s2 2s2 2p1 = 3 electron in its valence shell.

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3 years ago

What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)

Andrei [34K]

Answer:

pH = 3.65

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer that is express as

pH = pKa + log(salt÷acid) ........................1

put here value and we get

pH = 3.40 + log(0.200÷0.110)

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A laboratory requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solutio

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3 years ago

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