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koban [17]
3 years ago
9

How many liters will 2.76 mol CO2 occupy? 2.76 mol II

Chemistry
1 answer:
sergeinik [125]3 years ago
6 0

This problem is providing information about the moles of carbon dioxide, 2.76 mol, and asks for the volume this amount takes up, turning out to be 61.8 L according to the Avogadro's law:

<h3>Avogadro's law:</h3><h3 />

In chemistry, gas laws are used to relate the behavior of gases by virtue of the their pressure, volume, temperature and moles; thus several gas laws exist for us to do so, however, we here focus on the Avogadro's law which relates the volume and moles when both temperature and pressure are held constant.

In such a way, since no information on the constant variables is given, we assume the mentioned carbon dioxide is at STP, (0 °C and 1 atm), which means that we can use the following equivalence statement derived from the ideal gas law (PV=nRT):

22.4 L = 1 mol

Hence, we calculate the required volume:

2.76molCO_2*\frac{22.4L\ CO_2}{1molCO_2} =61.8L\ CO_2

Learn more about ideal gases: brainly.com/question/11676583

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3 0
4 years ago
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A sample of potassium phosphate octahydrate (K3PO4•8H2O) is heated until 7.93 grams of water are released. How many grams did th
Gekata [30.6K]

The original sample of potassium phosphate octahydrate had a mass of 19.6 grams. When it was heated, it released 7.93 grams of water.

Further Explanation:

For every mole of the compound potassium phosphate octahydrate, there are 8 moles of water of hydration which can be removed from the crystal by heating without altering the chemical composition of the substance.

To determine how much original sample was used, the amount of water released upon heating may be used as well as the mole ratio of the water of hydration with the compound itself following the steps below:

  1. Convert mass of water released to moles.
  2. Use the mole ratio of water of hydration to the compound (8 mol water for every mol of potassium phosphate octahydrate) to get the moles of original sample.
  3. Convert the moles of original sample to grams.

STEP 1: Convert 7.93 g water to moles.

moles \ of\ H_{2}O \ = 7.93 \ g \ H_{2}O \ (\frac{1 \ mol \ H_{2}O}{18.00 \ g \ H_{2}O})\\\boxed {moles \ of \ H_{2}O \ = 0.4406 \ mol}

STEP 2: Calculate the moles of original sample using the mole ratio: 1 mol K3PO4 8H2O : 8 mol H2O.

moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.4406 \ mol \ H_{2}O \ (\frac{1 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ }{8 \ mol \ H_{2}O})\\\\\boxed {moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.0551 \ mol}

STEP 3: Convert the moles of original sample to mass.

mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 0.0551 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ (\frac{356.3885 \ g}{1 \ mol\ K_{3}PO_{4}\ 8H_{2}O})\\ mass \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 19.637 \ g

Following the significant figures of the given, the final answer should be:

\boxed {mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 19.6 \ g}

Learn More:

  1. Learn more about water of hydration brainly.com/question/6053815
  2. Learn more about mole conversion brainly.com/question/12979299
  3. Learn more about percent hydrate brainly.com/question/12398621

Keywords: water of hydration, hydrate

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Which statement best compares the properties of compounds and elements that the compounds contain?
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