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koban [17]
2 years ago
9

How many liters will 2.76 mol CO2 occupy? 2.76 mol II

Chemistry
1 answer:
sergeinik [125]2 years ago
6 0

This problem is providing information about the moles of carbon dioxide, 2.76 mol, and asks for the volume this amount takes up, turning out to be 61.8 L according to the Avogadro's law:

<h3>Avogadro's law:</h3><h3 />

In chemistry, gas laws are used to relate the behavior of gases by virtue of the their pressure, volume, temperature and moles; thus several gas laws exist for us to do so, however, we here focus on the Avogadro's law which relates the volume and moles when both temperature and pressure are held constant.

In such a way, since no information on the constant variables is given, we assume the mentioned carbon dioxide is at STP, (0 °C and 1 atm), which means that we can use the following equivalence statement derived from the ideal gas law (PV=nRT):

22.4 L = 1 mol

Hence, we calculate the required volume:

2.76molCO_2*\frac{22.4L\ CO_2}{1molCO_2} =61.8L\ CO_2

Learn more about ideal gases: brainly.com/question/11676583

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Answer:

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Explanation:

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The oxygen molecule is split in their two atoms of O. The element which has 1 proton and 1 electron is the hydrogen (H). So, when hydrogen reacts with oxygen, they form water (H₂O).

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3 years ago
What happens if you don't disconnect the wires in a series circuit?
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Answer:

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Explanation:

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5 0
2 years ago
If a tree dies and the trunk remains undisturbed for 13,750 years, what percentage of the original 14c is still present? (the ha
defon

Answer:

18.94%.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
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<em>kt = ln [A₀]/[A]</em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = 13,750 years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = ??? %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(13,750 years) = ln (100.0%)/[A]

1.664 =  ln (100.0%)/[A]

Taking exponential for both sides:

5.279 = (100.0%)/[A]

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