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2 years ago

How many liters will 2.76 mol CO2 occupy? 2.76 mol II

1 answer:

6 0

This problem is providing information about the moles of carbon dioxide, 2.76 mol, and asks for the volume this amount takes up, turning out to be 61.8 L according to the Avogadro's law:

<h3>Avogadro's law:</h3><h3 />

In chemistry, gas laws are used to relate the behavior of gases by virtue of the their pressure, volume, temperature and moles; thus several gas laws exist for us to do so, however, we here focus on the Avogadro's law which relates the volume and moles when both temperature and pressure are held constant.

In such a way, since no information on the constant variables is given, we assume the mentioned carbon dioxide is at STP, (0 °C and 1 atm), which means that we can use the following equivalence statement derived from the ideal gas law (PV=nRT):

22.4 L = 1 mol

Hence, we calculate the required volume:

$2.76molCO_2*\frac{22.4L\ CO_2}{1molCO_2} =61.8L\ CO_2$

Learn more about ideal gases: brainly.com/question/11676583

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PLEASE ANSWER ASAP:

sergij07 [2.7K]

Answer:

True

Explanation:

Heat is a kind of energy.

The kinetic theory relates the heat with the movement of the particles: the more the particles move, the larger the kinetic energy of the system. The kinetic theory states that heat is the kinetic energy of the particles, atoms or molecules, in a substance, that is transferred from a substance at higher temperature to other substance at lower temperature.

Based on that principle, the kinetic theory explains the changes of phases of the substances in terms of the motion of the particles: the hotter an object the faster the particles move, the more energetic the particles are, and they occupy more space. Thus, when a solid is heated, the particles move faster and it can pass to liquid or gaseous state.

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3 years ago

What volume of 0.200 M H2SO* will be needed to neutralize 50.00 mL of 0.178 MNaOH?

mixas84 [53]

Answer:

10.00 mL

Explanation:

Please, do not forget to write the dot and 2 of Zeros after the number 10 in the answer!

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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3 years ago

7. List all of the variables that you controlled or kept the same. Salt water

satela [25.4K]

Answer:

Temperature is a common type of controlled variable. If a temperature is held constant during an experiment, it is controlled. Other examples of controlled variables could be an amount of light, using the same type of glassware, constant humidity, or duration of an experiment.

Explanation:

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3 years ago

Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re

blondinia [14]

M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x 0.0512 => 0.0057856 moles of NaOH

mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- 0.0057856 moles NaOH

(moles HCl ) = 0.0057856 x 1 / 1

= 0.0057856 moles of HCl

M ( HCl ) = n / V

M = 0.0057856 / 0.0255

= 0.227 M

Answer A

hope this helps!

4 0

3 years ago

Read 2 more answers

How many miles of O2 can be produced by letting 12.00 miles of KC103 react?

Marat540 [252]

2KClO3 --> 2KClO2 + O2
12 6 (moles)
The ratio of KClO3 and O2 is 2:1. This means 2 moles of KClO3 can create 1 mole of O2. So 12 moles of KClO3 will create 6 moles of O2.

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2 years ago