Answer:
ohm
Explanation:
Given data:
capacitor = 0.5 micro farad
resistor = 500 ohm
Frequency = 2000 Hz
Impedance of any circuit is calculated by using following equation
=500 - j 159.155
ohm
Answer:While structured analysis sees procedures and information as isolated segments, object-oriented (O-O) analysis joins information and the procedures that follow up on the information into things called objects. O-O analysis utilizes protest models to show information, conduct, and by what implies objects influence different articles. By portraying the items (information) and techniques (forms) expected to help a business task, a framework engineer can outline reusable segments for quicker framework usage and diminished advancement cost.Numerous experts trust that, contrasted and organized examination, O-O strategies are more adaptable, effective, and reasonable in the present unique business environment. Agile improvement techniques have pulled in a wide after and a whole network of clients.
Agile strategies ordinarily utilize a winding model, which speaks to a progression of cycles, or revisions,which depend on client criticism. Advocates of the winding model trust that this approach lessens dangers and accelerates programming advancement. Investigators ought to perceive that lithe techniques have points of interest and hindrances. By their tendency, dexterous strategies enable designers to be considerably more adaptable and responsive, however can be less secure than more customary techniques.For instance, without a point by point set of framework necessities, certain highlights asked for by a few clients won't not be predictable with the organization's bigger course of action. Other potential disservices of versatile strategies can incorporate feeble documentation, obscured lines of responsibility, and too little accentuation on the bigger business picture. Additionally, except if legitimately executed, a long arrangement of emphases may really add to extend cost and advancement time.
Answer:
give the question in English it'd be understandable
Answer:
a) 14.285
b) 8.956
Explanation:
Given :
The combustion of the ethanol is with air
Air is 21% oxygen
and, 79% nitrogen
thus, for 1 O₂ we have (79/21)N₂
thus,
the stochiometric equation for the combustion is as:
C₂H₅OH + 3[O₂ + (79/21)N₂] ⇒ 2CO₂ + 3H₂O + 3 × (79/21)N₂
Now,
the molecular weight of the fuel (C₂H₅OH) = (2× 12) + (5 × 1) + 16 + 1 = 46 g/mol
Molecular weight of the air = (2 × 16) + ((79/21) × 28) = 137.33 g/mol
a) air/fuel ratio on a molar basis
we have
air-fuel ratio = moles of air / moles of fuel
or
air-fuel ratio = [3 × 1 + 3 × (79/21)] / 1 = 14.285
b) air/fuel ratio on a mass basis = Mass of air / mass of fuel
or
air/fuel ratio on a mass basis = (number of moles of air × molar mass of air) / (number of moles of fuel × molar mass of fuel)
on substituting the values, we have
air/fuel ratio on a mass basis = (3 × 137.33) / (1 × 46) = 8.956