section 10.1 describes a man in the middle attack on the diffie-hellman key exhange protocal in which the adversary generates tw
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Answer:
a) 154054 gals
b) 20850 lb/day
c) 0.7392hr
d) 2.466day^-1
e) 7.23 lb/day-1000 ft^3
Explanation:
a)
b)
Dry mass = 5 MGD * (0.20) * (2500 mg/l) * 8.34 = 20850 lb/day
c)
Aeration period Q =
d)
e)
BOD loading =
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Answer:
i) SF = 0.83
ii) 10 psi
iii) 3.16 psi
iv) 0.0083
Explanation:
Constant load = 1000 Psi
mean resistance = 1200 psi
Probability of failure = 1.9 * 10^-3
<u>Determine </u>
<u>i) Safety factor </u>
S.F = 1 / (mean load / load design ) = 1 / ( 1200 / 1000 ) = 0.83
<u>ii) Standard deviation </u>
1.9 X 10^-3 = e ( -1/2 ( μ / б) ^3 / (2.5 * 6 )
0.004756 = e^- 20000 / б^3
hence std = 10 psi
<u>iii) Variance </u>
= = 3.16 psi
<u>iv) coefficient of variation </u>
Cv = std / mean resistance
= 10 / 1200 = 0.0083
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