Answer:
Estimated number of indigenous faults remaining undetected is 6
Explanation:
The maximum likelihood estimate of indigenous faults is given by,
here,
= the number of unseeded faults = 6
= number of seeded faults = 30
= number of seeded faults found = 15
So NF will be calculated as,
And the estimate of faults remaining is = 12 - 6 = 6
Answer:
Explanation:
A suitable calculator can show you the vector components and their resultant in polar or rectangular format. (See attached.) 2D vectors are conveniently treated as complex numbers, which is why the y-component values are shown as imaginary.
(The 50° angle measured from the -x axis is equivalent to 130° measured from the +x axis, which is the reference we're using here.)
If you'd like to compute the vector components by hand, they are ...
(x, y) = magnitude×(cos(angle), sin(angle))
This notation is sometimes abbreviated <em>magnitude cis angle</em>, a reference to the complex number form x+yi.
Answer:
Explanation:
Using equation of pure torsion
where
T is the applied Torque
is polar moment of inertia of the shaft
t is the shear stress at a distance r from the center
r is distance from center
For a shaft with
Outer Diameter
Inner Diameter
Applying values in the above equation we get
x
Thus from the equation of torsion we get
Applying values we get
T =829.97Nm
Answer:
The displacement from t = 0 to t = 10 s, is -880 m
Distance is 912 m
Explanation:
. . . . . . . . . . A
integrate above equation we get
from information given in the question we have
t = 1 s, s = -10 m
so distance s will be
-10 = 12 - 1 + C,
C = -21
we know that acceleration is given as
[FROM EQUATION A]
Acceleration at t = 4 s, a(4) = -24 m/s^2
for the displacement from t = 0 to t = 10 s,
the distance the particle travels during this time period:
let v = 0,
t = 2 s
Distance