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Citrus2011 [14]
3 years ago
11

Tyrell bought 6 video games this summer. Each game cost 27 dollars. If Tyrell had 379 dollars left after he bought the video gam

es, how much money did he start with?
Mathematics
2 answers:
Rudiy273 years ago
7 0

Tyrell started with 541 $

There are two actions in the question.

First Tyrell bought 6 video games, each game cost 27 $.

Spent

According to that Tyrell spent

6 * 27 = 162 $

Keeps

The second fact is that after shopping Tyrell keeps 379 $.

If Tyrell spent 162 $ and still keeps 379 $, that means that the total amount of money Tyrell had is the sum of the money he spent plus the money he has

Now if we call "x" the quantity of money Tyrrel started with: Then

x  =  the money Tyrell spent on video games  plus the remaining 379 $

Then

x  =  162  + 379

x = 541 $

xxMikexx [17]3 years ago
6 0

<u><em>Tyrell started with $541.</em></u>

First you must know the total amount of money spent on the games. For that Tyrell bought 6 video games this summer and each game cost 27 dollars. So to calculate the amount spent, the number of games purchased must be multiplied by the price of each one:

6 video games* 27 dollars each game= 162 dollars

So Tyrell spends 162 dollars.

On the other hand, you know that Tyrell had 379 dollars left after he bought the video games. This indicates that after spending $ 162 on video games, there were $ 379 left over. To know the amount of money that Tyrell had, you must add the amount spent on games and the money that was left over:

162 dollars + 379 dollars= 541 dollars

So, <u><em>Tyrell started with $541.</em></u>

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Answer:

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Step-by-step explanation:

two hundred sixty-five thousandths= 0.265

We need a number between 1 and 10, to do the multiplication in standard form, so 0.265 turns into 2.65.

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Step-by-step explanation:

there is 2 grey marbles so 2/10 (there is 10 marbles altogether)

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Answer:

\large \boxed{\$35.80}  

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Use the tests for divisibility to determine which numbers divide evenly into the given number.
drek231 [11]

The numbers that can divide 648 evenly, using the divisibility tests, include <u>1, 2, 3, 4, 6, 8, 9, 12, and 18</u> and some multiples of any two numbers.

<h3>What is the divisibility test?</h3>

A divisibility test is performed to identify whether a number can be divided evenly by a fixed divisor without a remainder and without actually performing the division process.

<u>Divisibility by 1</u>: Every number is divisible by 1 = 648 (648/1).

<u>Divisibility by 2</u>: 648 is an even number and divisible by 2 = 324.

<u>Divisibility by 3</u>: Sum the digits (18). 18 is divisible by 3 = 6 (18/3).

<u>Divisibility by 4</u>: The last two digits (4 and 8) form a number (12) that is divisible by 4

<u>Divisibility by 6</u>:  It is divisible by 2 and by 3

<u>Divisibility by 8</u>: If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.

<u>Divisibility by 9</u>: Sum the digits (18). 18 is divisible by 9

<u>Divisibility by 12</u>: 648 is divisible by 3 and by 4.

<u>Divisibility by 18</u>: 648 is divisible by 2 and by 9.

Learn more about the divisibility tests at brainly.com/question/24125354

#SPJ1

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