Answer : The energy for vacancy formation in silver is, 
Explanation :
Formula used :
or,
So,
![N_v=[\frac{N_A\times \rho}{M}]\times e^{(\frac{-E}{K\times T})}](https://tex.z-dn.net/?f=N_v%3D%5B%5Cfrac%7BN_A%5Ctimes%20%5Crho%7D%7BM%7D%5D%5Ctimes%20e%5E%7B%28%5Cfrac%7B-E%7D%7BK%5Ctimes%20T%7D%29%7D)
where,
= equilibrium number of vacancies = 
E = energy = ?
M = atomic weight = 107.9 g/mole
= Avogadro's number = 
= density = 
T = temperature = 
K = Boltzmann constant = 
Now put all the given values in the above formula, we get:
![3.6\times 10^{20}L^{-1}=[\frac{(6.022\times 10^{23}mol^{-1})\times 9500g/L}{107.9g/mol}]\times e^{[\frac{-E}{(1.38\times 10^{-23}J/K)\times 1073K}]}](https://tex.z-dn.net/?f=3.6%5Ctimes%2010%5E%7B20%7DL%5E%7B-1%7D%3D%5B%5Cfrac%7B%286.022%5Ctimes%2010%5E%7B23%7Dmol%5E%7B-1%7D%29%5Ctimes%209500g%2FL%7D%7B107.9g%2Fmol%7D%5D%5Ctimes%20e%5E%7B%5B%5Cfrac%7B-E%7D%7B%281.38%5Ctimes%2010%5E%7B-23%7DJ%2FK%29%5Ctimes%201073K%7D%5D%7D)
Therefore, the energy for vacancy formation in silver is,
Answer:
41.3 s
Explanation:
Let t₁ represent the time taken for SO₂ to effuse.
Let t₂ represent the time taken for Ar to effuse.
Let M₁ represent the molar mass of SO₂
Let M₂ represent the molar mass of Ar
From the question given above,
Time taken (t₁) for SO₂ = 52.3 s
Time taken (t₂) for Ar =?
Molar mass (M₁) of SO₂ = 32 + (16×2) = 32 + 32 = 64 g/mol
Molar mass (M₂) of Ar = 40 g/mol
Finally, we shall determine the time taken for Ar to effuse by using the Graham's law equation as shown below:
t₂ / t₁ = √(M₂ / M₁)
t₂ / 52.3 = √(40 / 64)
t₂ / 52.3 = √0.625
t₂ / 52.3 = 0.79
Cross multiply
t₂ = 52.3 × 0.79
t₂ = 41.3 s
Thus, the time taken for the amount of Ar to effuse is 41.3 s
Answer:
transfer
Explanation:
as heat flows from one object to another, the first object loses the heat(energy), while the second object gains heat(energy).
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Explanation:
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Answer:
0.25 mol/L
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 4L
Initial concentration (C1) = 0.5 mol/L
Final volume (V2) = 4 + 4 = 8L
Final concentration (C2) =?
Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:
C1V1 = C2V2
0.5 x 4 = C2 x 8
Divide both side by 8
C2 = (0.5 x 4 )/ 8
C2 = 0.25 mol/L
Therefore the concentration of the diluted solution is 0.25 mol/L
