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pshichka [43]
3 years ago
11

How many moles of O2 are produced when 0.425 mol of KO2 reacts in this fashion

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
4 0
The chemical reaction is expressed as:

<span> 4KO2+2CO2→2K2CO3+3O2 
</span>
We are given the amount of KO2 to be used in the reaction. This will be the starting point of our calculations. We do as follows:

0.425 mol KO2 ( 3 mol O2 / 4 mol KO2 ) = 0.319 mol O2 produced

Hope this answers the question. Have a nice day.
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Write a balanced half-reaction describing the oxidation of solid chromium to aqueous chromium(IV) cations.
Pachacha [2.7K]

Answer:

Cr(s) ⟶ Cr⁴⁺(aq) + 4e⁻  

Explanation:

1. Write the skeleton half-reaction

Cr(s) ⟶ Cr⁴⁺(aq)

2. Balance charge

Add electrons to the side that needs them.

You have 4+ on the right and 0 on the left. You must add 4e⁻ to the right to balance the charge.

Cr(s) ⟶ Cr⁴⁺(aq) + 4e⁻

7 0
3 years ago
The palmetto landfill in greer, sc supplies over 50% of the energy for the bmw plant there. this reduces carbon dioxide emission
Verdich [7]
Hello there!

The answer is 92000 tons per year

The palmetto landfill supplies methane (CH₄) for the BMW plant there. The gas is used to operate the turbines used to power the BMW campus. It reduces carbon dioxide emissions because the combustion of methane produces fewer CO₂ than the combustion of other gases like propane or butane, which are commonly used for powering turbines. 
4 0
3 years ago
What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]​
valentinak56 [21]

Answer: The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%

Given: mass of sulphur = 32 g/mol

mass of Al_2(SO_4)_3 = 342 g/mol

Putting in the values we get:

{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%

The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

4 0
3 years ago
The noble gases are inert due to the fact that A. their valence shell is empty B. their valence shell is full C. their electrons
coldgirl [10]

Answer:

B) Their valence shell is full

Explanation:

In order to be classified as a noble gas, an element must have a complete octet/ a full shell of valence electrons, as shown in answer B.

A and C are just incorrect. Since noble gasses are very unstable, D is a true statement, but is isn't the correct answer as this does not explain why they are inert.

<h3>Hope this was helpful!</h3>
5 0
3 years ago
Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.5 x 102 J Moles of H3PO4 = 1.4 x 1
OlgaM077 [116]
Below are the steps to get the answers:

<span>1.) write out the balance equation 3NaOh+H3PO4->Na3PO4+3H2O
 
2.) You are given everything needed to calculate q=heat transfer=2.2*10^2, H3PO4 moles= 1.5*10^-3, NaOH moles=5.0*10^-3
 
3.) equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first
 
4.) Now plug in variables DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole Notice we had to convert J to kj, </span>
7 0
3 years ago
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