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pshichka [43]
3 years ago
11

How many moles of O2 are produced when 0.425 mol of KO2 reacts in this fashion

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
4 0
The chemical reaction is expressed as:

<span> 4KO2+2CO2→2K2CO3+3O2 
</span>
We are given the amount of KO2 to be used in the reaction. This will be the starting point of our calculations. We do as follows:

0.425 mol KO2 ( 3 mol O2 / 4 mol KO2 ) = 0.319 mol O2 produced

Hope this answers the question. Have a nice day.
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Describe what happens in the cell before the chemical reaction.
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Answer:

Chemical reactions that take place inside living things are called biochemical reactions. The sum of all the biochemical reactions in an organism is referred to as metabolism. Metabolism includes both exothermic (heat-releasing) chemical reactions and endothermic (heat-absorbing) chemical reactions.

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6 0
3 years ago
Which of these agreements has goals of peace and shared scientific research?
Jet001 [13]

Option C, Antarctic Treaty System, is the right answer.

The Antarctic Treaty System, control global connections with regard to Antarctica; the only continent of the earth without the native population of human beings. In other words, the ATS is the entire system of adjustments developed for the intention of managing associations among states in the Antarctic. The main goal of the ATS is to guarantee "in the affair of all humankind that Antarctica shall proceed always to be practised completely for peaceful objectives and shall not become the view or gadget of universal disharmony.

8 0
3 years ago
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Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
DanielleElmas [232]

Answer:

74.4 ml

Explanation:

          C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given     15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0
3 years ago
10. There are two bears that both have the same proteins for ear shape in their cells. The bears have
valentinak56 [21]

Answer:

They will have the same ear shape since their proteins connect in the same ways to determine ear shape.

Explanation:

I majored in Chemistry

4 0
2 years ago
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How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.33138 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0
3 years ago
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