Answer:
b) Vectors A and B are in the same direction.
Explanation:
To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).
The length of the resultant vector will be 5 - 3 = 2
In the attached image, we analyze case a), b), and d)
For a)
As we can see in the attached image the resultant vector has a length of 8 units.
For d)
As we can see in the attached image the resultant vector has a length of 5.83 units.
For b)
The resultant vector has a length of 2 units.
Therefore the case given in b) is true
Answer:
the time taken for the motion is 3.37 s
Explanation:
Given;
initial velocity of the skydiver, u = 0
final velocity of the skydiver, v = 33 m/s
The time taken for the motion is calculated as;
v = u + gt
33 = 0 + 9.8t
33 = 9.8t
t = 33 / 9.8
t = 3.37 s
Therefore, the time taken for the motion is 3.37 s
The radius of the cylinder is equal to half the diameter:
The volume of the cylinder is given by:
where h is the heigth of the cylinder. Converting into meters,
And the density of the material will be given by the ratio between the mass and the volume:
The model bridge captures all the structural attributes of the real bridge, at a reduced scale.
Part a.
Note that volume is proportional to the cube of length. Therefore the actual bridge will have 100^3 = 10^6 times the mass of the model bridge.
Because the model bridge weighs 50 N, the real bridge weighs
(50 N)*10^6 = 50 MN.
Part b.
The model bridge matches the structural characteristics of the actual bridge.
Therefore the real bridge will not sag either.
