Answer:
160N
Explanation:
Moments must be conserved - so.
the friction force provided by the brakes is 30000 N.
<h3>What is friction force?</h3>
Friction force is the force that opposes the motion between two bodies in contact.
To calculate the average friction force provided by the brakes, we apply the formula below.
Formula:
- K.E = F'd............. Equation 1
Where:
- K.E = Kinetic energy of the train
- F' = Friction force provided by the brakes
- d = distance
Make F' the subject of the equation
- F' = K.E/d............ Equation 2
From the question,
Given:
Substitute these values into equation 2
- F' = (8.1 ×10⁶)/270
- F' = 30000 N
Hence, the friction force provided by the brakes is 30000 N
Learn more about friction force here: brainly.com/question/13680415
The answer is 10,560 Joules or 1.1*10^4
Explanation:
Step 1: Calculate
The equation for Kinetic Energy is
Kinetic energy=.5 times Mass times Velocity²
KE=.5*m*v²
so we plug in our numbers
KE=.5*600*35.2²
This works out to be 10,560 Joules or 1.1*10^4
