Question

In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separation between adjacent bright fringes on a screen 5 m from the slits is: CONVERT FIRST

Answer 1

Answer:

The  value is  $y = 0.0025 \ m$

Explanation:

From the question we are told that

   The  wavelength is  $\lambda = 500 \ nm$

    The distance of separation is  $d = 1\ mm = 0.001 \ m$

   The  distance from the screen is  $D = 5 \ m$

Generally the separation between the adjacent bright fringe is mathematically represented as

       $y = \frac{D * \lambda }{ d}$

=>    $y = \frac{5 * 500 *10^{-9}}{0.001}$

=>    $y = 0.0025 \ m$