1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naily [24]
3 years ago
5

Which of the following bonds is the strongest? H-H C-CI C=O N-N

Chemistry
2 answers:
Marina86 [1]3 years ago
6 0

Answer:

C=O

Explanation:

We are given that

H-H

C-Cl

C=O

N-N

We know that single bonds are weaker than the double bonds. It can says that the double bonds are stronger than the single bonds.The single bond is formed between two electrons and double bonds are formed between four electrons.

When double bonds are formed between two atoms then one is sigma bond and other is pi bond .Sigma bonds are formed by hybridization between s- s orbital and pi bonds are formed between un-hybridized p- orbitals.

Therefore, Double bonds are stronger than the single bond.Hence, C=O is strongest bond.

Answer: In  C=O the bond  is strongest bond.

Arisa [49]3 years ago
4 0
Double bonds are stronger than single bonds. So C=O.
Hope it helps!
You might be interested in
How is acids and bases connected to Physical Science?
Arada [10]
An acid is an ionic compound that produces positive hydrogen ions when dissolved in water. Acids taste sour and turn blue litmus paper red. A base is an ionic compound that produces negative hydroxide ions when dissolved in water. Bases taste bitter and turn red litmus paper blue.
8 0
3 years ago
Read 2 more answers
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio
brilliants [131]

Explanation:

The given data is as follows.

          Concentration of standard NaOH solution = 0.1922 M

Let the original acid solution concentration be x.

                        M_{1}V_{1} = M_{2}V_{2}

                        x \times 25 = 250 \times M_{2}

                         M_{2} = \frac{x \times 25}{250}

                                     = 0.1 x M

V_{2} = 10.00 mL (given)

The reaction equation is as follows.

             2NaOH + H_{2}SO_{4} \rightarrow Na_{2}SO_{4} + 2H_{2}O

   Concentration × Volume of H_{2}SO_{4} = Concentration × Volume of NaOH

           \frac{M_{2}V_{2}}{n_{2}} = \frac{M_{3}V_{3}}{n_{3}}

     \frac{0.1 x \times 10 ml}{1} = \frac{0.1922 M \times 13.68 ml}{2}

                  x = 1.314 M

Therefore, we can conclude that the concentration of the original sulfuric acid solution is 1.314 M.

7 0
3 years ago
What is a mountain system
zloy xaker [14]
A mountain system is a geographic area containing numerous geologically realted mountains.
5 0
3 years ago
Calculate the energy change when an electron moves from n=5 to n=7. Explain/show work please.
Korolek [52]

Answer: E = 1.55 ⋅ 10 − 19 J

Explanation:  

The energy transition will be equal to  1.55 ⋅ 10 − 1 J .  

So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition

1 λ  = R ⋅ ( 1 n 2 final  − 1 n 2 initial  ) , where λ - the wavelength of the emitted photon; R

- Rydberg's constant -  1.0974 ⋅ 10 7 m − 1 ; n final - the final energy level - in your case equal to 3; n initial - the initial energy level - in your case equal to 5. So, you've got all you need to solve for  λ , so 1 λ  =

1.0974 ⋅10  7 m − 1 ⋅ (....     −152    

)

1

λ

=

0.07804

⋅

10

7

m

−

1

⇒

λ

=

1.28

⋅

10

−

6

m

Since  

E

=

h

c

λ

, to calculate for the energy of this transition you'll have to multiply Rydberg's equation by  

h

⋅

c

, where

h

- Planck's constant -  

6.626

⋅

10

−

34

J

⋅

s

c

- the speed of light -  

299,792,458 m/s

So, the transition energy for your particular transition (which is part of the Paschen Series) is  

E

=

6.626

⋅

10

−

34

J

⋅

s

⋅

299,792,458

m/s

1.28

⋅

10

−

6

m

E

=

1.55

⋅

10

−

19

J

8 0
3 years ago
What is the percent of carbon in carbonate?
Sedaia [141]

Answer:

The percentage of carbon in a 55 % pure sample of carbon carbonate is. (Ca=40, C=12, O=16)

Explanation:

Hope this helps!!!!!!!!!!

3 0
3 years ago
Other questions:
  • Part ii 1. the solubility of _____________ is least affected by temperature. (name of substance)
    5·1 answer
  • How does a buffer resist change in ph upon addition of a strong acid?
    15·1 answer
  • How many carbons are in a molecule of hexane?<br> a. 2<br> b. 4<br> c. 6<br> d. 8
    14·1 answer
  • The nonvolatile, nonelectrolyte cholesterol, C27H46O (386.60 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressure
    10·1 answer
  • Total distance divided by total elapsed time gives what quantity?
    12·1 answer
  • A gas occupies 25.3 at pressure of 790.5 mmHg. Determine the volume if the pressure is reduced to 8.04 mmHg
    5·1 answer
  • Convert 6.71 moles NH3 to number of molecules.
    10·1 answer
  • If you decreased the volume of a sample of gas by a factor of three while maintaining a constant
    11·2 answers
  • Which one help!<br> Chemistry
    6·1 answer
  • Explain the bonding that occurs between sodium and chlorine. Specifically, what kind of bonding takes
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!