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miss Akunina [59]

3 years ago

13

s-Block compounds give a characteristic flame colour in the flame test. Based on this, can you give one use of s-block compounds

?

1 answer:

Sophie [7]3 years ago

3 0

Answer:

Lithium is used in making electrochemical cells.

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What would happen when a substance changes from one phase to another? A. The substance loses or gains heat. B. The average kinet

lutik1710 [3]

I think the correct answer from the choices listed above is option B. When a substance changes from one phase to another, the average kinetic energy of the substance <span>changes since the molecules movements are changed as well. Hope this answers the question. Have a nice day.</span>

3 0

3 years ago

True or False: Anushka set out to create something to measure

SpyIntel [72]

I think is true not sure but it might be

7 0

4 years ago

Read 2 more answers

The following boiling points correspond to the substances listed. Match the boiling points to the substances by considering the

Julli [10]

Answer:

CH₄ - 162 ⁸C

CH₃CH₃ -88.5 ⁸C

(CH₃)₂ CHCH₂CH₃ 28 ⁸C

CH₃3(CH2)₃CH₃ 36 ⁸C

CH₃OH 64.5 ⁸C

CH₃CH₂OH 78.3 ⁸C

CH₃CHOHCH₃ 82.5 ⁸C

C₅H₉OH 140 ⁸C

C₆H₅CH₂OH 205 ⁸C

HOCH₂CHOHCH₂OH 290 ⁸C

Explanation:

To answer this question we need first to understand that for organic compounds:

a. Non polar compounds have lower boiling points than polar ones of similar structure and molecular weight.

b. Boiling points increase with molecular weight. In alkane compounds if we compare isomers, the straight chain isomer will have a higher boiling point than the branched one (s) because of London dispersion intermolecular forces.

a. The introduction of hydroxyl groups increase the intermolecular forces and hence the boiling points because the electronegative oxygen, and, more importantly the presence of hydrogen bonds.

Considering the observations above, we can match the boiling points as follows:

CH₄ - 162 ⁸C

CH₃CH₃ -88.5 ⁸C

(CH₃)₂ CHCH₂CH₃ 28 ⁸C

CH₃3(CH2)₃CH₃ 36 ⁸C

CH₃OH 64.5 ⁸C

CH₃CH₂OH 78.3 ⁸C

CH₃CHOHCH₃ 82.5 ⁸C

C₅H₉OH 140 ⁸C

C₆H₅CH₂OH 205 ⁸C

HOCH₂CHOHCH₂OH 290 ⁸C

Note: There was a mistake in the symbols used for the 162 and 88.5 values which are negative and correspond to the common gases methane and ethane

7 0

3 years ago

What’s the amino acid for this?

Pachacha [2.7K]

The amino acid for this should be Arginine. I am not entirely sure.

5 0

2 years ago

What is the final pressure, in mmHg, for a gas in an aerosol can at an initial pressure of 1.40 atm at 12°C which is heated to 3

liubo4ka [24]

Answer:

b. 1150 mmHg

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

Gay Lussac Law - $\frac{P_1}{T_1} =\frac{P_2}{T_2}$

P₁ is Pressure 1
T₁ is Temperature 1 in Kelvin
P₂ is Pressure 2
T₂ is Temperature 2 in Kelvin

Explanation:

<u>Step 1: Define</u>

P₁ = 1.40 atm

T₁ = 12°C

P₂ = unknown

T₂ = 35°C

<u>Step 2: Identify Conversions</u>

1 atm = 760 mmHg

K = °C + 273.15

<u>Step 3: Convert</u>

P₁ = 1.40 atm = 1064 mmHg

T₁ = 12°C = 285.15 K

T₂ = 35°C = 308.15 K

<u>Step 4: Find P₂</u>

Substitute: $\frac{1064 \ mmHg}{285.15 \ K} =\frac{P_2}{308.15 \ K}$
Cross-multiply: $(1064 \ mmHg)(308.15 \ K)=P_2(285.15 \ K)$
Multiply: $327872 \ mmHg \cdot K=P_2(285.15 \ K)$
Isolate P₂: $\frac{327872 \ mmHg \cdot K}{285.15 \ K}=P_2$
Divide: $1149.82 \ mmHg=P_2$
Rewrite: $P_2=1149.82 \ mmHg$

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1149.82 mmHg ≈ 1150 mmHg

4 0

3 years ago