The answer is 110., but round accordingly
The heat lost is 
The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.
<h3>Heat Transfer</h3>
This is the heat transferred from a body of higher temperature to a body of lower temperature.

- Q = Heat Transfer
- m = mass = 1277g
- ΔT = change in temperature

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.
Solving for heat transfer

The heat loss is approximately 
Learn more on heat transfer here;
brainly.com/question/16055406
Answer:
The correct answer is - 13.33 kJ of heat
Explanation:
To know which one is the limiting reagent, determine the number of moles of each reagent in order .
n(K) = mass/atomic weight = 1.41/39 = 0.036 moles
Density of ICl = Mass/Volume
3.24 = Mass/6.52
Mass of ICl = 21.12 g
n(ICl) = mass/molar mass = 21.12/162.35 = 0.130 moles
2 moles of K reacts with 1 mole of ICl
0.036 moles of K will react with = 0.036/2 = 0.018 moles of ICl
since the amount of moles of ICl is more than 0.018, it is in excess and hence K is the limiting reagent. Now, use the balance equation to determine the amount of heat liberated:
2 moles of K gives out -740.71 kJ of heat
1 mole of K will give out = -740.71/2 = 370.36 kJ of heat
0.036 moles of K will give out = 0.036 × 370.36 = 13.33 kJ of heat
Thus, the correct answer is - 13.33 kJ of heat
Answer is: molar mass of molecular compound is 71,95 g/mol.
N(compound) = 8,35·10²¹.
n(compound) = N(compound) ÷ Na.
n(compound) = 8,35·10²¹ ÷ 6,022·10²³ 1/mol.
n(compound) = 0,0139 mol.
m(compound) = 1,00 g.
M(compound) = m(compound) ÷ n(compound).
M(compound) = 1 g ÷ 0,0139 mol.
M(compound) = 71,95 g/mol.
Answer:
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