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2 years ago

Which of the following solutions of glucose in water will have the lowest freezing point?

Chemistry

1 answer:

Neko [114]2 years ago

4 0

Answer:

Explanation:

Colligative properties are properties that depend on the amount of substance present.

Freezing point is a colligative property hence it depends on the number of moles of the glucose present in solution. The bigger the concentration of the glucose molecules, the greater the freezing point depression. So, the largest freezing point depression is observed for the solution having the highest concentration of glucose.

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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the

Makovka662 [10]

The empirical formula of this compound is $Fe_2O_3$

<h3>Empirical formula </h3>

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

$MM_O = 16g/mol\\MM_Fe = 55.8g/mol$

$MM = \frac{m}{mol}$

$16 = \frac{4.8}{x}$

$x = 0.3mol$

$55.8=\frac{11.2}{x}\\x = 0.2$

As the value of the empirical formula must be an integer, simply multiply the two values by a common factor:

$O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2$

$Fe_2O_3$

So, the empirical formula of this compound is $Fe_2O_3$ .

Learn more about empirical formula: brainly.com/question/1247523

3 0

1 year ago

What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N

Citrus2011 [14]

<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis
Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.68873 \ g \ Mg_3N_2$