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Oduvanchick [21]
3 years ago
11

Which of the following solutions of glucose in water will have the lowest freezing point?

Chemistry
1 answer:
Neko [114]3 years ago
4 0

Answer:

B

Explanation:

Colligative properties are properties that depend on the amount of substance present.

Freezing point is a colligative property hence it depends on the number of moles of the glucose present in solution. The bigger the concentration of the glucose molecules, the greater the freezing point depression. So, the largest freezing point depression is observed for the solution having the highest concentration of glucose.

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HELP PLEASE!! 20 POINTSS
Mrac [35]
The answer is 110., but round accordingly
3 0
2 years ago
How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points
OLga [1]

The heat lost is -7.32*10^-^5J

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

<h3>Heat Transfer</h3>

This is the heat transferred from a body of higher temperature to a body of lower temperature.

Q = mc(\delta)T

  • Q = Heat Transfer
  • m = mass = 1277g
  • ΔT  = change in temperature

\delta T = (400 - 273) - (263 - 273) = \\&#10;\delta T = T_2 - T_1\\&#10;\delta T = -10 - 127\\&#10;\delta T = -137^0C

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

Q = mc\delta T\\&#10;Q = 1277 * 4.186 * -137\\&#10;Q = -732336.514J

The heat loss is approximately -7.32*10^-^5J

Learn more on heat transfer here;

brainly.com/question/16055406

6 0
2 years ago
How much heat is liberated at constant pressure when 1.41 g of potassium metal reacts with 6.52 mL of liquid iodine monochloride
Lemur [1.5K]

Answer:

The correct answer is -  13.33 kJ of heat

Explanation:

To know which one is the limiting reagent, determine the number of moles of each reagent in order .

n(K) = mass/atomic weight = 1.41/39 = 0.036 moles

Density of ICl = Mass/Volume

3.24 = Mass/6.52

Mass of ICl = 21.12 g

n(ICl) = mass/molar mass = 21.12/162.35 = 0.130 moles

2 moles of K reacts with 1 mole of ICl

0.036 moles of K will react with = 0.036/2 = 0.018 moles of ICl

since the amount of moles of ICl is more than 0.018, it is in excess and hence K is the limiting reagent. Now, use the balance equation to determine the amount of heat liberated:

2 moles of K gives out -740.71 kJ of heat

1 mole of K will give out = -740.71/2 = 370.36 kJ of heat

0.036 moles of K will give out = 0.036 × 370.36 = 13.33 kJ of heat

Thus, the correct answer is -  13.33 kJ of heat

7 0
3 years ago
If 1.00 g of an unknown molecular compound contains 8.35  1021 molecules, what is its molar mass?
scoray [572]
Answer is: molar mass of molecular compound is 71,95 g/mol.
N(compound) = 8,35·10²¹.
n(compound) = N(compound) ÷ Na.
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n(compound) = 0,0139 mol.
m(compound) = 1,00 g.
M(compound) = m(compound) ÷ n(compound).
M(compound) = 1 g ÷ 0,0139 mol.
M(compound) = 71,95 g/mol.
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Answer:

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