3 years ago

Which of the following solutions of glucose in water will have the lowest freezing point?

Chemistry

1 answer:

Neko [114]3 years ago

4 0

Answer:

Explanation:

Colligative properties are properties that depend on the amount of substance present.

Freezing point is a colligative property hence it depends on the number of moles of the glucose present in solution. The bigger the concentration of the glucose molecules, the greater the freezing point depression. So, the largest freezing point depression is observed for the solution having the highest concentration of glucose.

You might be interested in

Which is true of a liquid?

Oksanka [162]

Answer would be c hope this helped

3 0

3 years ago

The chemical equation below is correctly balanced.

DIA [1.3K]

Answer:

44.8 L of O2 will react (option D)

Explanation:

Step 1: Data given

Number of moles of SO2 = 4.00 moles

STP = Pressure = 1 atm and temperature = 273 K

Step 2: The balanced equation

2 SO2(g) + O2(g) → 2 SO3(g)

Step 3: Calculate moles of O2

For 2 moles SO2, we need 1 mol O2 to produce 2 moles SO3

For 4.00 moles SO2 we need 4.00 / 2 = 2.00 moles O2

Step 4: Calculate volume of O2

For 1 mol we have a volume of 22.4 L

V = (n*R*T)/ p

V = (2.00 * 0.08206 * 273)/p

V = 44.8 L

For 2.00 moles we have a volume of 2*22.4 = 44.8 L

44.8 L of O2 will react (option D)

8 0

3 years ago

I created a typical vinegar and baking soda experiment. About 100 ml of white vinegar, and 100ml of baking soda. Once the reacti

olganol [36]

It is 20 because then you will put 30 inside of 20milimeeter and put 70 years into the other pint and put it learnt into the cup

7 0

1 year ago

An atom has 2 protons in its nucleus. Which of the following must be true for this atom to have no net electrical charge?

sp2606 [1]

The 2 correct options I guess are A and D

3 0

3 years ago

Read 2 more answers

What volume of a 0.424 M CO2 solution are needed to produce 63.58 mL of 0.731 M solution of K2CO3?

cricket20 [7]

Answer:

Socratic app

Explanation:

it will help you

6 0

3 years ago