The pressure of a gas depends on the temperature and volume of the gas.
<h3>Ideal gas equation</h3>
PV = nRT
Where
- P is the pressure
- V is the volume
- n is the number of mole
- R is the gas constant
- T is the temperature
From the equation given above, we obtained the following:
PV = nRT
Divide both sides by V
P = nRT / V
R is constant and n = 1
P = T / V
Thus, we can see that the pressure (P) is dependent on the temperature (T) and the volume (V)
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Answer:
0.25 mol/L
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 4L
Initial concentration (C1) = 0.5 mol/L
Final volume (V2) = 4 + 4 = 8L
Final concentration (C2) =?
Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:
C1V1 = C2V2
0.5 x 4 = C2 x 8
Divide both side by 8
C2 = (0.5 x 4 )/ 8
C2 = 0.25 mol/L
Therefore the concentration of the diluted solution is 0.25 mol/L
D.
The products will have at least 2 Na atoms and 1 O atom.
<h3>Further explanation</h3>
If we refer to the law of mass conservation, which states that
<em>In a closed system, the masses before and after the reaction are the same
</em>
then the number of atoms in the reactance will be the same as the number of atoms in the product
In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O
Like an example of this Na₂O reaction:
Na₂O + H₂O ⇒ 2 NaOH
Na : left =2, right = 2
O : left=2, right = 2
The answer is 80 atomic mass
Answer:
Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g
Explanation:
SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.
the balanced chemical equation is as follows
Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O
Moles of Na₂SO₃ = 
Moles of HCl = 
using mole ratio method to find limiting reagent
For sodium sulfite 
for HCl 
since <u>sodium sulfite</u> is <u>limiting reactant</u> for above chemical reaction
1 mole of Na₂SO₃ produce 1 mole of SO₂
0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂
∴ Mass of SO₂ produce = mole x molar mass of SO₂
= 0.198 x 64
= 12.672 g
