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lesantik [10]
3 years ago
12

How many grams of water are in 19.2 moles of water? *#28 is the question

Chemistry
1 answer:
PtichkaEL [24]3 years ago
8 0
The grams of water produced is c

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Determine the [OH-], pH, and pOH of a solution with a [H+] of 0.090 M at 25 °C. [OH-] = pH = pOH = 0 POH =
ValentinkaMS [17]

Answer : The concentration of OH^- ion, pH and pOH of solution is, 1.12\times 10^{-13}M, 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of H^+ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

pH=-\log [H^+]

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.090)

pH=1.05

The pH of the solution is, 1.05

Now we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-1.05=12.95

The pOH of the solution is, 12.95

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12.95=-\log [OH^-]

[OH^-]=1.12\times 10^{-13}M

The OH^- concentration is, 1.12\times 10^{-13}M

5 0
3 years ago
Read 2 more answers
Calculate the ph of a solution formed by mixing 250. 0 ml of 0. 15 m nh4cl with 200. 0 ml of 0. 12 m nh3. the kb for nh3 is 1. 8
Phantasy [73]

The potential of the hydrogen in water gives the pH of the acidity and basicity of the solution. The pH of the solution is 9.06. Thus, option iii is correct.

<h3>What is pH?</h3>

The pH of a substance is given by the subtraction of the pOH from 14 which is the range of the pH scale.

The dissociation reaction for ammonia is given as,

NH₃ (aq) + H₂O (l)  ⇄  NH₄⁺ (aq) + OH⁻ (aq)

Here, the concentration of ammonia is [NH₃] - x, ammonium ion is [NH₄⁺] + x, and hydroxide ion is x.

The molar concentration of ammonia is,

M = (0.12 M × 0.2 L) ÷ 0.45 L = 0.053 M

The molar concentration of ammonium ion is,

M = (0.15 M × 0.25 L) ÷ 0.45 L = 0.083 M

From the base dissociation constant and previous concentration from the reaction, the value of x or hydroxide ion is calculated as,

Kb = [NH₄⁺][OH⁻] ÷ [NH₃]

1.8 × 10⁻⁵ (0.053 - x) - (0.083 + x) × x = 0

x = [OH⁻] = 1.15 x 10⁻⁵

The pH from the hydroxide ion is calculated as,

pOH = - log [OH⁻]

= - log (1.15 x 10⁻⁵)

= 4.94

Further,

pH = 14 - pOH

= 14 - 4.94

= 9.06

Therefore, option iii. 9.06 is the pH of the solution.

Learn more about pH here:

brainly.com/question/14790520

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4 0
1 year ago
Please help on how to solve this problem it’s for isotopes
wlad13 [49]

Mg-19:

#protons = 12

#neutrons = 7

#electrons = 12

Mg-40:

#protons = 12

#neutrons = 28

#electrons = 12

8 0
2 years ago
Identify each of the following compounds as: (a) a nonelectrolyte: lactose (c12h22o11) potassium chloride (kcl) lactic acid (hc3
11Alexandr11 [23.1K]

Nonelectrolytes are compounds that do not tend to get ionize in all solution. As a result, solutions which contains nonelectrolytes will not conduct electricity.

Ionic compounds dissolve in water and break into the constituent ions through the process called ionization. Now These electrolyte solutions can either be acids, or bases, or salts.

If  the process of ionization produces a large no. of ions in the solution, it is a strong electrolyte. On the other hand, if it produces only a few ions, the solution is a weak electrolyte,

Potassium chloride (KCL) is a strong electrolyte,

Lactic acid (HC3H503) is a weak electrolyte,

Whereas, Ethanol (C3H7OH) is a non electrolyte,

Dimethylamine (CH3)2NH is a weak electrolyte,

Sodium hydroxide(NaOH) is a strong electrolyte.

To learn more about nonelectrolytes, head here

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6 0
1 year ago
A cell using protein-mediated facilitated diffusion is treated with a toxin that prevents conformation change in the membrane pr
seraphim [82]

Answer:

The most likely outcome is that carrier protein dysfunction will increase the gradient which will lead to disruption of cellular metabolism.

3 0
3 years ago
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