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3 years ago

What is the name of the ionic compound Csmc010-1.jpgS? cesium sulfur cesium sulfide dicesium sulfur dicesium sulfide

Chemistry

2 answers:

Anna007 [38]3 years ago

7 0

Answer:

cesium sulfide

Explanation:

nika2105 [10]3 years ago

5 0

Answer is: cesium sulfide.
Formula for ionic compound is: Cs₂S.
Ionic compound <span>electrically </span>neutral, cesium has charge +1 (2· (+1) = +2) and sulfur has charge -2.
Cesium sulfide is whide powder, soluble in water, pyrophoric in dry air, reductant.

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3 years ago

Need some help with this problem please!

Tom [10]

Answer:

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Explanation:

Step 1: Figure out what the formula and what you are dealing with.

- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.

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- Step 2: Rearrange the equation to fit this problem, you should get...

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3 years ago

witch can be classified as a trace fossil A. dinosur bone B. srimp burrow C. imprint on a fern leaf D. mold of a clam shell

kakasveta [241]

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Explanation:

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3 years ago

Read 2 more answers

For an alloy that consists of 91.0 g copper, 111 g zinc, and 7.51 g lead, what are the concentrations (a) of Cu (in at%), (b) of

viktelen [127]

Answer:

$\% Cu=45.2\%\\\\\% Zn=53.6\%\\\\\% Pb=1.2\%$

Explanation:

Hello!

In this case, given the masses of copper, zinc and lead, it is possible to compute the moles via their atomic masses first:

$n_{Cu}=\frac{91.0gCu}{63.55g/mol}=1.432mol\\\\ n_{Zn}=\frac{111gZn}{65.41g/mol}=1.697mol\\\\n_{Pb}=\frac{7.51gPb}{207.2g/mol}=0.0362mol\\$

Now, we compute the atomic percentages as shown below:

$\% Cu=\frac{1.432}{1.432+1.697+0.0362}*100\% =45.2\%\\\\\% Zn=\frac{1.697}{1.432+1.697+0.0362}*100\%=53.6\%\\\\\% Pb=\frac{0.0362}{1.432+1.697+0.0362}*100\%=1.2\%$

Best regards!

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2 years ago