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3 years ago

What is the name of the ionic compound Csmc010-1.jpgS? cesium sulfur cesium sulfide dicesium sulfur dicesium sulfide

Chemistry

2 answers:

Anna007 [38]3 years ago

7 0

Answer:

cesium sulfide

Explanation:

nika2105 [10]3 years ago

5 0

Answer is: cesium sulfide.
Formula for ionic compound is: Cs₂S.
Ionic compound <span>electrically </span>neutral, cesium has charge +1 (2· (+1) = +2) and sulfur has charge -2.
Cesium sulfide is whide powder, soluble in water, pyrophoric in dry air, reductant.

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How sulphuric acid react with Glucose ? Give reaction

Ierofanga [76]

Answer:

Concentrated sulfuric acid can perform a dehydration reaction with table sugar. After mixing, the color changes from white to brownish and eventually to black. The expansion of the mixture is the result of vaporization of water and CO2 inside the container.

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3 years ago

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For the reaction between aqueous solutions of acetic acid (CH3COOH) and barium hydroxide, Ba(OH)2, write

borishaifa [10]

Answer:

See explanation.

Explanation:

Hello!

In this case, since we are asked to note down the complete molecular equation, complete ionic equation and the net ionic equation for the reaction between acetic acid (weak acid) and barium hydroxide (strong base), we proceed as shown below:

- Complete molecular equation:

$2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)$

- Complete ionic equation: in this case, since acetic acid is a weak one, it is not ionized, so we do this:

$2CH_3COOH(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow Ba^{2+}(aq)+2CH_3COO^-(aq)+2H_2O(l)$

- Net ionic equation: in this case, we cancel out the barium ions as they are the spectators one because they are present at both reactants and products:

$2CH_3COOH(aq)+2OH^-(aq)\rightarrow 2CH_3COO^-(aq)+2H_2O(l)\\\\CH_3COOH(aq)+OH^-(aq)\rightarrow CH_3COO^-(aq)+H_2O(l)$

Best regards!

3 0

3 years ago

This element has 50 electrons in a neutral atom and is usually mixed with metals to form an alloy.

babymother [125]

Heya!

HERE IS YOUR ANSWER:

Electrons = 50

Atomic number = 50

so, the Element is stannum (Sn)

6 0

3 years ago

A 25 mL sample of 0.100 M HNO3 completely reacts with NaOH according to this equation:

Anastasy [175]

It is a good thing that you already have answered the first question. Now, moving on to the second question, there exist an equation for the neutralization of acid by a base that is shown below,
M₁V₁ = M₂V₂
Now, all the variables in the equation are given except for our unknown which is the V₂. Substituting the known values from the given above,
(0.1 M)(25 mL) = (0.05 M)(V₂)
The value of V₂ from the equation above is 50 mL. Therefore, 50 mL of 0.05 M NaOH solution will be needed to completely react with HNO3.

6 0

3 years ago

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What is the percentage composition of each element in Fe(OH)3

Bezzdna [24]

Answer:

Fe =52.2%, O = 44.9%, H = 2.81%

Explanation:

Percentage composition is also known as percentage by mass.

First, find the Mr of the compound.

Mr of Fe(OH)₃ = 55.8 + (16 × 3) + (1 × 3)

= 106.8