A force of 200N acts between two objects at a certain distance apart .the value of the force when the distance is halved is?
1 answer:
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Answer:(a) 50 N
(b)38.34 N
Explanation:
Given
Maximum tension(T) in line 50 N
(a)If line is moving up with constant velocity i.e. there is no acceleration
This will happen when Tension is equal to weight of Fish
T-mg=0
T=mg
Maximum weight in this case will be 50 N
(b)acceleration of magnitude
T-mg=ma
m=3.91
Therefore weight is