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WITCHER [35]
3 years ago
5

Compare the motions of transverse, longitudinal, and combined waves.

Physics
1 answer:
notsponge [240]3 years ago
4 0

Explanation:

transfer to babes are always at your advice by a particular motion being a particular wave motion along didn't wave is a wave which particular is a medium move a direction parallel to the direction of the wave moves something that is similar in the surveys on the medium moves of the same direction and bathe an accident to one or two Dimensions do in London killing babe attacks in one dimension and transverse waves attacks in two Dimensions the Waze cannot be paralyzed or organized

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A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

3 0
4 years ago
A 10-kg object is dropped from rest. after falling a distance of 50 m, it has a speed of 26 m/s. what is the change in mechanica
likoan [24]

The change in mechanical energy caused by the dissipative resistance force is equal to, difference between the potential energy and kinetic energy of the object.

Potential energy of the object, P.E = mgh

m is mass of the object = 10 kg

g is acceleration due to gravity = 9.8 m/s²

h= height from which it is dropped =50 m

Substituting the value we get,

P.E = 10×9.8×50 = 4900 J

Kinetic energy of the object, K.E = \frac{1}{2}mv^{2}

v is the velocity of the object = 26 m/s²

K.E = (1/2)×10×(26)²

= 3380 J

Change in mechanical energy caused by dissipative force = P.E ₋ K.E

= 4900 ₋ 3380 = 1520 J

4 0
3 years ago
Ball a of mass 5.0 kilograms moving at 20 meters per second collides with ball b of unknown mass moving at 10 meters per second
RUDIKE [14]

M = mass of the ball A = 5.0 kg

m = mass of the ball B = ?

V = initial velocity of the ball A before collision = 20 m/s

v = initial velocity of the ball B  before collision = 10 m/s

V' = final velocity of the ball A after collision = 10 m/s

v' = final velocity of the ball B after collision = 15 m/s

using conservation of momentum

M V + m v = M V' + m v'

(5.0) (20) + m (10) = (5.0) (10) + m (15)

100 + 10 m= 50 + 15 m

5 m = 50

m= 10 m/s



4 0
3 years ago
URGENT HELP NEEDED PLEASE!
GenaCL600 [577]

Answer:

the total energy before collision is 12.25J

the total energy after collision is tranfered to sound and heat (by the friction between the two clay balls)

Explanation:

first we should know the velocity of the 2 balls:

momentum=mass ×velocity

we have the momentum and the mass of the 2

so momentum ÷mass=velocity

clay ball 1 velocity=7 m/s & clay ball 2 velocity= -7 m/s

KE=1/2 mv²

1/2 ×0.25×7²=6.125J KE of ball 1

1/2 ×0.25×-7²=6.125J KE of ball 2

add them both we will have 12.25J which is before collision

this energy will then be tranfered to heat and sound as they stop after the collision(velocity =0m/s)

8 0
3 years ago
If an athlete completes a cycle around a circular track, his displacement eauals to ZERO.
RSB [31]

The statement is <em>TRUE</em>.

"Displacement" means the distance and direction from the start-point to the end-point, NO MATTER how you got there.

If you go out cycling and go back home when you're done, your displacement is zero.  it doesn't matter how far you cycled, or what streets or woods you cycled through, or whether your route was a circle, a square, an ellipse, a triangle, or a jumble, or whether you cycled around and around the same path 27 times.  You ended right where you started.  The distance from your start-point to your end-point is zero, so your displacement is zero.

3 0
3 years ago
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