If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result?
1 answer:
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The pictures are not attached, therefore, I cannot give a specific choice.
However, I will try to help you out.
The angle of incidence is defined as the angle formed between the ray of light and the normal to the surface that the ray is falling on.
The angle of incidence can be shown in the attached image.
Therefore, for your question, choose the image on which the above description applies.
Hope this helps :)
However, I will try to help you out.
The angle of incidence is defined as the angle formed between the ray of light and the normal to the surface that the ray is falling on.
The angle of incidence can be shown in the attached image.
Therefore, for your question, choose the image on which the above description applies.
Hope this helps :)
Answer:
μsmín = 0.1
Explanation:
- There are three external forces acting on the riders, two in the vertical direction that oppose each other, the force due to gravity (which we call weight) and the friction force.
- This friction force has a maximum value, that can be written as follows:
where μs is the coefficient of static friction, and Fn is the normal force,
perpendicular to the wall and aiming to the center of rotation.
- This force is the only force acting in the horizontal direction, but, at the same time, is the force that keeps the riders rotating, which is the centripetal force.
- This force has the following general expression:
where ω is the angular velocity of the riders, and r the distance to the
center of rotation (the radius of the circle), and m the mass of the
riders.
Since Fc is actually Fn, we can replace the right side of (2) in (1), as
follows:
- When the riders are on the verge of sliding down, this force must be equal to the weight Fg, so we can write the following equation:
- (The coefficient of static friction is the minimum possible, due to any value less than it would cause the riders to slide down)
- Cancelling the masses on both sides of (4), we get:
- Prior to solve (5) we need to convert ω from rev/min to rad/sec, as follows:
- Replacing by the givens in (5), we can solve for μsmín, as follows: