What is the difference between a physical quantity and a unit
1 answer:
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The crate is moving at constant velocity when the forces acting on it are
balanced.
- The value of the force <em>F</em> required to pull the crate with constant velocity is;
Reasons:
Mass of the crate = m
Cross section of through = Right angled
Orientation (inclination) of the through to horizontal = 45°
Coefficient of kinetic friction = μ
Required:
The value of the required to pull the crate along the through at constant
velocity.
Solution:
When the through is moving at constant velocity, we have;
Friction force acting on crate = Force pulling the crate
Friction force = Normal reaction × Coefficient of kinetic friction
Normal reaction on an inclined plane =
Each side of the through gives a normal reaction.
The vertical component of the normal reaction on each side of the through
is therefore;
·j =
× sin(θ)
The sum of the vertical component = ·j +
·j = 2·
·j = 2·
×sin(θ)
The sum of the vertical component of the normal reactions = The weight of the crate
Therefore;
2·×sin(θ) = m·g
θ = 45°
Therefore;
2·×sin(45°) = m·g
Therefore;
Which gives;
- Force required to pull the crate at constant velocity, <u>F = √2·μ·m·g</u>
Learn more about force of friction here:
Answer:
Explanation:
When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:
where
q is the charge
v is its velocity
B is the strength of the magnetic field
Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:
where
m is the mass of the particle
r is the radius of the orbit of the particle
The equation can be re-arranges as
where in this problem we have:
is the magnitude of the charge of the electron
is the strength of the magnetic field
The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,
is the mass of the electron
So, the electron's speed is