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Ne4ueva [31]
3 years ago
9

HELP

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

Answer:

It's Tan.

Multiple Thumbs-up ^_^

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A. 28.8<br> B. 22.5<br> C. 27.2<br> D. 26.8
Rashid [163]
X/sin 42 = 43/sin 87

x = (43 * sin 42)/(sin 87)

x = 28.812

Answer: 28.8
5 0
3 years ago
Can someone plz help? It's algebra, and if you cant help, plz don't answer.
skelet666 [1.2K]

Answer:The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is solid and goes through the points negative 3, 0, negative 4, negative 1 and is shaded in below the line. The other line is solid, and goes through the points 1, 1, 2, negative 1 and is shaded in below the line

Step-by-step explanation:y ≤ −2x + 3 y ≤ x + 3 y ≥ −2x + 3 y ≥ x + 3 y ≤ −3x + 2 y ≤ −x + 2 y > −2x + 3 y > x + 3

3 0
3 years ago
Read 2 more answers
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
One member of a gardening club can plant flowers in 12 hours. With two members of the club working together the job can be done
mariarad [96]

Answer:

24 hours

Step-by-step explanation:

One member of the gardening club can alone plant flowers in 12 hours.

So in 1 hour he can plant 1/12 of the flowers.

Let the time required by the second member of the club to plant flowers alone be x hours.

Then in 1 hour he can plant 1/x of the flowers.

Now when the two members work together,each hour they can plant:

\[\frac{1}{12}+\frac{1}{x}\] of the flowers.

But they can together complete the job in 8 hours. So in one hour they plant 1/8 of the flowers.

=> \[\frac{1}{12}+\frac{1}{x}=\frac{1}{8}\]

=> \[\frac{1}{x}=\frac{1}{24}\]&#10;

=> x=24

So the second member can plant the flowers alone in 24 hours

4 0
3 years ago
write the ratio as a percent 6 per 100 , 49 out of 100 , 16 per 100 , 21 out of 100 , 80 per 100 , 93 out of 100​
DedPeter [7]

Answer:

6%, 49%, 16%, 21%, 80%, 93%

Step-by-step explanation:

add the percent sign to each each number (6, 49, 16, 21, 80, and 93).

6 0
3 years ago
Read 2 more answers
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