Given:
μ=106.3 minutes
σ=18.5 minutes
Need to find
P(80<x<95)=>
P(x)=Z((95-μ)/σ)-Z((80-μ)/σ)
=Z(-0.61081)-Z(-1.42162)
=0.27066-0.077568
=0.1931
Therefore probability of customers waiting between 80 and 95 minutes is 0.1931
So, the formula is C=5/9(F-32)
You would substitute the 50C for C:
50 = 5/9 (F - 32)
Divide both sides by 5/9 (or multiply by the reciprocal)
90 = F - 32
Add the 32 to both sides:
122 = F
So, 50C = 122F
Answer:
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Step-by-step explanation:
p^2-3p(3/2)^2=8+(3/2)^2
p^2-(3/2)^2=8+9/4
√(p-3÷2)^2=√(8+9÷4) take LCM and cancel out the square and square root
p-3÷2=√(32+9÷4)
p=(3+_√41÷2)
