Answer:
the wavelength of radiation emitted is 
Explanation:
The energy of the Bohr's hydrogen atom can be expressed with the formula:
For n = 7:
For n = 4
The electron goes from the n = 7 to the n = 4, then :
Wavelength of the radiation emitted:
where;
hc = 1242 eV.nm
Answer:
The answer to your question is the letter B
Explanation:
I will draw the skeletal structures of these compounds to determine which alcohol is secondary.
Secondary alcohol is alcohol in which the hydroxyl group is attached to a secondary alcohol.
Letter A has primary and secondary alcohol so I discard this choice.
Letter B has secondary alcohol, so this is the correct choice.
The letter C has a primary and 2 secondary alcohols so I discard this choice.
Answer:
CH4 - Methane
B2Si - Diboron monosilicide
N2O5 - Dinitrogen pentoxide
CO2 - Carbon dioxide
Explanation:
When it comes to naming covalent compounds, there are several rules.
The name is derived based on the formula. For example, N2O5. The first element is nitrogen. To the name of the element, you add the prefix that tells us how many of its atoms are in the compound. In this case, there are two atoms, which means that the prefix will be <em>di</em>- (dinitrogen). The second element is oxygen. You are supposed to take only the root of the second element's name and then add the prefix denoting the number of its atoms and the suffix <em>-ide</em> (pentoxide). This is how we'll get dinitrogen pentoxide.
The only exception is methane (CH4), which is an organic compound. Organic compounds are named using the IUPAC nomenclature.
Explanation:
the answer will be A
The catalyst cannot be at point A since that's the reactant
Pathway B requires more energy, which makes it slower and harder for the reaction to finish
point D is the product
Answer:
The charge on H is partial positive and the charge on I is partial negative.
δ+H−Iδ−
The percent ionic character is 5.15 %.
Explanation:
The ionic compound is formed by the complete transfer of electron from one atom to another. The one atom thus carry the positive charge while the other which accept the electron became negative. like in case of NaCl .This have 100% ionic character.
In covalent bond, the bond is formed by the sharing of electron between two atoms. The one atom which greatly pull the electrons towards itself is became partial negative while the other became partial positive atom. In this way electronegativity difference is created. For example in HI bond hydrogen is partial positive and have 2.2 electronegativity while the electronegativity of iodine is 2.66.
Percent ionic character:
Formula:
%ionic character = [1- e∧-(0.25)(x)²] × 100
X= XA - XB
XA = higher electronegativity
XB = lower electronegativity
X = 2.66 - 2.2
X = 0.46
now we will determine the %ionic character.
%ionic character = [1- e∧-(0.25)(x)²] × 100
%ionic character = [1- e∧-(0.25)(0.46)²] × 100
%ionic character = [1- e∧-(0.25)(0.2116)] × 100
%ionic character = [1- e∧-(0.0529)] × 100
%ionic character = [1- 0.9485)] × 100
%ionic character = 0.0515 × 100
%ionic character = 5.15%
