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Brut [27]
3 years ago
12

NEED HELP ASAP!!!!! PLEASE HELP!!!!! NEED HELP ASAP!!!!!

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

CH4 - Methane

B2Si - Diboron monosilicide

N2O5 - Dinitrogen pentoxide

CO2 - Carbon dioxide

Explanation:

When it comes to naming covalent compounds, there are several rules.

The name is derived based on the formula. For example, N2O5. The first element is nitrogen. To the name of the element, you add the prefix that tells us how many of its atoms are in the compound. In this case, there are two atoms, which means that the prefix will be <em>di</em>- (dinitrogen). The second element is oxygen. You are supposed to take only the root of the second element's name and then add the prefix denoting the number of its atoms and the suffix <em>-ide</em> (pentoxide). This is how we'll get dinitrogen pentoxide.

The only exception is methane (CH4), which is an organic compound. Organic compounds are named using the IUPAC nomenclature.

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Suppose 0.795 g of sodium iodide is dissolved in 100. mL of a 39.0 m M aqueous solution of silver nitrate.
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The final molarity of iodide anion is 0.053 M

Explanation:

<u>Step 1</u>: Data given

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Volume of the solution = 100 mL = 0.1 L

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The molecular mass of sodium iodide is 149.89 g/mol.

<u>Step 2:</u> The balanced equation

AgNO3(aq) + NaI(aq) → AgI(s) + NaNO3(aq)

<u>Step 3: </u>Calculate number of moles of sodium iodide

Moles NaI = mass NaI / Molar mass NaI

Moles NaI = 0.795 grams / 149.89 g/mol

Moles NaI = 0.0053 moles

For 1 mole AgNO3 consumed, we need 1 mole NaI to produce 1 mole AgI and 1 mole NaNO3

The sodium iodide will dissociate as followed:

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<u>Step 4</u>: Calculate iodide ions

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