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Brut [27]
3 years ago
12

NEED HELP ASAP!!!!! PLEASE HELP!!!!! NEED HELP ASAP!!!!!

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

CH4 - Methane

B2Si - Diboron monosilicide

N2O5 - Dinitrogen pentoxide

CO2 - Carbon dioxide

Explanation:

When it comes to naming covalent compounds, there are several rules.

The name is derived based on the formula. For example, N2O5. The first element is nitrogen. To the name of the element, you add the prefix that tells us how many of its atoms are in the compound. In this case, there are two atoms, which means that the prefix will be <em>di</em>- (dinitrogen). The second element is oxygen. You are supposed to take only the root of the second element's name and then add the prefix denoting the number of its atoms and the suffix <em>-ide</em> (pentoxide). This is how we'll get dinitrogen pentoxide.

The only exception is methane (CH4), which is an organic compound. Organic compounds are named using the IUPAC nomenclature.

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2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
Due in minutes! Please Help Solve!
stiks02 [169]
Step by step equation
5 0
3 years ago
3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?
Leno4ka [110]

Answer:

Option A (9.0) is the correct alternative.

Explanation:

The given values are:

Molarity,

= 1.5 M

Volume,

= 6000 mL

or,

= 6 L

As we know,

⇒ Molarity=\frac{Moles}{Volume}

or,

⇒ The \ moles \ of \ NaCl=Molarity\times Volume

By putting the values, we get

                                     =1.5\times 6

                                     =9 \ mol

7 0
3 years ago
The chemical properties of a substance can only be observed when it is changed into a different substance. True or False
HACTEHA [7]
I am pretty sure that the answer is true
6 0
3 years ago
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Is the process represented below an example of a physical or a chemical
Basile [38]
It is a physical change because only the states as being changes, not the actual bonds in the compound.
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