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igor_vitrenko [27]
3 years ago
7

An example of a secondary alcohol is *

Chemistry
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

The answer to your question is the letter B

Explanation:

I will draw the skeletal structures of these compounds to determine which alcohol is secondary.

Secondary alcohol is alcohol in which the hydroxyl group is attached to a secondary alcohol.

Letter A has primary and secondary alcohol so I discard this choice.

Letter B has secondary alcohol, so this is the correct choice.

The letter C has a primary and 2 secondary alcohols so I discard this choice.

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Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Montano1993 [528]

The question is incomplete, here is the complete question:

Urea (CH₄N₂O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH₃) with carbon dioxide as follows: 2NH₃(aq) + CO₂(aq) → CH₄N₂O(aq) + H₂O(l) In an industrial synthesis of urea, a chemist combines 135.9 kg of ammonia with 211.4 kg of carbon dioxide and obtains 178.0 kg of urea.

Determine the limiting reactant. (express your answer as a chemical formula)

<u>Answer:</u> The limiting reactant is ammonia (NH_3)

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For ammonia:</u>

Given mass of ammonia = 135.9 kg = 135900 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{135900g}{17g/mol}=7994.12mol

  • <u>For carbon dioxide gas:</u>

Given mass of carbon dioxide gas = 211.4 kg = 211400 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon dioxide gas}=\frac{211400g}{44g/mol}=4804.54mol

The given chemical reaction follows:

2NH_3(aq.)+CO_2(aq,)\rightarrow CH_4N_2O(aq.)+H_2O(l)

By Stoichiometry of the reaction:

2 moles of ammonia reacts with 1 mole of carbon dioxide

So, 7994.12 moles of ammonia will react with = \frac{1}{2}\times 7994.12=3997.06mol of carbon dioxide

As, given amount of carbon dioxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ammonia is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reactant is ammonia (NH_3)

5 0
3 years ago
Using the black numbers on the stopwatch to answer the questions.
Rus_ich [418]

Answer: the top one is 5.3 s and the bottom one is tenths of seconds

Explanation:

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3 years ago
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KengaRu [80]

Answer:

water and oceans

Explanation:

the moons creates tides as it goes around the

earth. This creates a bulge on the side of the earth.

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7 0
3 years ago
Please answer it quickly
kirill [66]

Answer:

B.

A.

D.

A.

C.

Hope it helps..

Have a great day : )

3 0
3 years ago
NO links, please! I will be reporting and reporting all of the other links you answer
RoseWind [281]

Answer:

This should be correct "The biggest advantage of sexual reproduction versus asexual reproduction is genetic diversity. When a single organism reproduces asexually it produces an exact copy of the parent organism."

Explanation:

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