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ahrayia [7]
3 years ago
14

How long would it take a machine to do 5.000

Physics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

a

Explanation:

How long would it take a machine to do 5.000

joules of work if the power rating of the machine

is 100 watts?

You might be interested in
Ultrasound with a frequency of 4.257 MHz can be used to produce images of the human body. If the speed of sound in the body is t
shutvik [7]

Answer:

2.49 * 10^(-4) m

Explanation:

Parameters given:

Frequency, f = 4.257 MHz = 4.257 * 10^6 Hz

Speed of sound in the body, v = 1.06 km/ = 1060 m/s

The speed of a wave is given as the product of its wavelength and frequency:

v = λf

Where λ = wavelength

This implies that:

λ = v/f

λ = (1060) / (4.257 * 10^6)

λ = 2.49 * 10^(-4) m

The wavelength of the sound in the body is 2.49 * 10^(-4) m.

4 0
3 years ago
A 5.00-m-long uniform ladder, weighing 200 N, rests against a smooth vertical wall with its base on a horizontal rough floor, a
Morgarella [4.7K]

Answer:

0.488  m  

Explanation:

If θ be the angle ladder makes with the plane

cos θ = 1.2 / 5

Tan θ = 4.04

Let the height a person of weight 600 N  can climb be h from the ground .

Distance from the base point  where ladder touches the floor  = h / tanθ

= h / 4.04

Total reaction force = total downward force

R = 200 + 600

800 N

Frictional force = μ R

= .2 x 800

= 160 N

Taking moment of force about the point on the ladder  where it  touches the floor  and balancing them

200 x 1.2 x .5 + 600 x   h / tanθ  = μ R x  1.2 / tanθ ( reaction  at the top point of ladder where it touches the wall is  R₁ and

R₁ =μ R   )

= 200 x 1.2 x .5 + 600 x   h / tanθ  = 160 x 1.2 / tanθ

120  - 600 h / 4.04 = 47.52

120 - 47.52 = 600 h / 4.04

72.48= 148.51 h

h = 0.488  m  

=

5 0
3 years ago
A grindstone of mass 12 kg and radius 0.3 m is initially rotating freely at 48 rad/sec. An axe is brought into contact with the
lesya [120]

Answer:

I = 0.54\,kg\cdot m^{2}

Explanation:

1) The moment of inertia of the grindstone is:

I = \frac{1}{2}\cdot m \cdot r^{2}

I = \frac{1}{2}\cdot (12\,kg)\cdot (0.3\,m)^{2}

I = 0.54\,kg\cdot m^{2}

4 0
3 years ago
Read 2 more answers
87) Determine the equivalent resistances for the following circuits.
stepladder [879]

Answer:

15    and  11 ohms

Explanation:

First one =   For the parallel resistors 1 / (1/6 + 1/6 + 1/6) =   1/ (3/6 ) = 6/3 = 2 ohms   then add the 3 and the 10  = 15 ohms

second one    for the parallel portion   equiv =    (10+2)*24 / ( (10+2 + 24) = 8

  then add the  3 in series = 11 ohms

8 0
2 years ago
Please help me! I don't understand how to do this!
dezoksy [38]

From the information in the question, the acceleration of the cart is 2.55 ms-2.

We can find the acceleration using the following information from the question;

u = 0.9 m/s

v = 6 m/s

a =  2.0 seconds

But;

a = v - u/t

v = final velocity

u = initial velocity

t = time

a = 6 - 0.9/2 = 2.55 ms-2

Force= ma

m = mass

a = acceleration

F = 6 kg × 2.55 ms-2

F = 15.3 N

Learn more about acceleration: brainly.com/question/12134554

3 0
2 years ago
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