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3 years ago

14

Pls help i’ll give brainliest if you give a correct answer!!

2 answers:

barxatty [35]3 years ago

5 0

Answer:

third option is the most accurate

arsen [322]3 years ago

3 0

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

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A cart was pulled for a distance of 1 kilometer and the amount of work accomplished equaled 40,000 joules. With what force was t

goblinko [34]

Answer:

40 N

Explanation:

3 0

3 years ago

14) the formula k2s indicates that

Ivan

14.) c) there are two potassium ions for each ion of sulfur. 15.) b) Lithium fluoride. 16.) d) carbon-12 atom. 17.) <span>c) nonmetal fluorine.</span>

6 0

3 years ago

Two ice skaters, each with a mass of 72.0 kg, are skating at 5.45 m/s when they collide and stick together. If the angle between

Rudiy27

Answer:

The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.

Explanation:

To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.

By definition it is known that the conservation of the moment is given by:

$m_1v_1+m_2v_2=(m_1+m_2)v_f$

Our values are given by,

$m_1=m_2=72Kg$

As the skater 1 run in x direction, there is not component in Y direction. Then,

Skate 1:

$v_{x1}=5.45m/s$

$v_{y1}=0$

Skate 2:

$v_{x2} = 5.45*cos105= -1.41m/s$

$v_{y2} = 5.45*sin105 = 5.26m/s$

Then, if we applying the formula in X direction:

m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}

75*5.45-75*1.41=(75+75)v_{fx}

Re-arrange and solving for v_{fx}

v_{fx}=\frac{4.04}{2}

v_{fx}=2.02m/s

Now applying the formula in Y direction:

$m_1v_{y1}+m_2v_{y2}=(m_1+m_2)v_{fy}$

$0+75*5.25=(75+75)v_{fy}$

$v_{fy}=\frac{5.25}{2}$

$v_{fy}=2.63m/s$

Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.

6 0

3 years ago

At the Six Flags Great America amusement park in Gurnee, Illinois, there is a roller coaster that incorporates some of the lates

Citrus2011 [14]

Given that roller coaster is of tear drop shape

So the speed at the top is given as

v = 11 m/s

acceleration at the top is given as

a = 2.9 g

$a = 2.9(9.8) = 28.42 m/s^2$

now we know the formula of centripetal acceleration as

$a = \frac{v^2}{R}$

$28.42 = \frac{11^2}{R}$

$R = 4.26 m$

PART B)

now if the total mass is given as

m = 2821 kg

now the Net force will be given as

$F = ma$

$F = 2821 \times 28.42 = 80172.8 N$

Now by force equation we will have

$F_n + mg = ma$

$F_n + 2821(9.8) = 80172.8$

$F_n = 52527 N$

PART C)

If the radius of the loop is 14 m

speed is given by same v = 11 m/s

now the acceleration is given as

$a = \frac{v^2}{R}$

$a = \frac{11^2}{14} = 8.6 m/s^2$

PART D)

Now for normal force at the top is given by force equation

$F_n + mg = ma$

$F_n + 2821(9.8) = 2821(8.6)$

so here normal force is coming with negative sign so it will not be possible to complete the circular path in this case

So normal force will be ZERO

8 0

3 years ago

Example of electrical to mechanical

Sonja [21]

Answer:

dynamo generator could be the right ans

6 0

3 years ago

Read 2 more answers