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Rasek [7]
3 years ago
14

Pls help i’ll give brainliest if you give a correct answer!!

Physics
2 answers:
barxatty [35]3 years ago
5 0

Answer:

third option is the most accurate

arsen [322]3 years ago
3 0

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

You might be interested in
A(n) 6.6 kg bowling ball is rolling towards the bowling pins. If its momentum is 15.9 kg*m/s, how fast is it traveling, in m/s?
Vedmedyk [2.9K]

Answer:

2.4m/s towards the bowling pins

Explanation:

Given parameters:

Mass of the ball  = 6.6kg

Momentum of the ball  = 15.9kgm/s

Unknown:

Speed of the ball  = ?

Solution:

The momentum is the amount of motion a body posses;

      Momentum = mas x velocity

Insert the parameters and solve;

      15.9  = 6.6 x velocity

        velocity  = 2.4m/s towards the bowling pins

3 0
3 years ago
Could someone help me on #7?
ozzi

i would sat C then the impact is weaker

8 0
3 years ago
A 2000 Hz siren and a civil defense official are both at rest with respect to the ground. What frequency does the official hear
astra-53 [7]

Answer:

a)f_1 = 2070.6 Hz

b)f_2 = 1929.4 Hz

Explanation:

Apparent frequency of the siren is given as

f = \frac{v_{rel}}{\lambda}

as we know that the wavelength will remain the same as it is having originally

sowe know

\lambda = \frac{340}{2000}

\lambda = 0.17 m

a) Now when wind is blowing from source to official

so we have

v_{rel} = 340 + 12 = 352 m/s

so we have

f_1 = \frac{352}{0.17}

f_1 = 2070.6 Hz

b) Now when wind is from official to source

so we have

v_{rel} = 340 - 12 = 328 m/s

so we have

f_2 = \frac{328}{0.17}

f_2 = 1929.4 Hz

4 0
4 years ago
based on this scatter plot,whatcan you say about the relationship between study time and test scores?
siniylev [52]

Based on this scatter plot, I can say that in general, test scores vary directly with study time.  In other words, in a population large enough to reveal the direct relationship, the more time a student spends studying, the higher that student's test scores will be.

I didn't need a scatter plot to reveal that to me.  That's practically in the category of Law given to Moses at Sinai.

8 0
3 years ago
We wrap a light, nonstretching cable around a 10.0 kg kg solid cylinder with diameter of 38.0 cm cm . The cylinder rotates with
amm1812

Answer: 14.16

Explanation:

Given

d = 38cm

r = d/2 = 38/2 = 19cm = 0.19m

K.E = 510J

m = 10kg

I = 1/2mr²

I = 1/2*10*0.19²

I = 0.18kgm²

When it has 510J of Kinetic Energy then,

510J = 1/2Iω²

ω² = 1020/I

ω² = 1020/0.18

ω² = 5666.67

ω = √5666.67 = 75.28 rad/s

Velocity is the block, v = ωr

V = 75.28 * 0.19

V = 14.30m/s

The "effective mass" M of the system is

M = (14.0 + ½*10.0) kg = 19.0 kg

The motive force would be

F = ma

F = 14 * 9.8

F = 137.2N

so that the acceleration would be

a = F/m

a = 137.2/19

a = 7.22m/s²

Finally, using equation of motion.

V² = u² + 2as

14.3² = 0 + 2*7.22*s

204.49 = 14.44s

s = 204.49/14.44

s = 14.16m

6 0
3 years ago
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