Answer:
A
Explanation:
nitrogen has the similar properties because carbon is the opposite of oxygen
The values of x represents that number of moles of water molecules that is present per mole of the salt magnesium sulfate. To determine the value for this, we need to know how much is the water that is lost after heating the sample assuming that all of the water molecules are evaporated leaving only the unhydrated form of the salt. We calculate as follows:
Mass of hydrated salt = 3.484 g
Mass after heating = 1.701 g
Mass lost = 3.484 g - 1.701 g = 1.783 g
The mass lost is equal to the mass of water lost.
Moles water lost = 1.783 g ( 1 mol / 18.02 g ) = 0.0989 mol H2O
Moles of unhydrated salt = 1.701 g ( 1 mol / 120.37 g ) = 0.0141 mol MgSO4
moles water / moles MgSO4 = 0.0989 mol H2O / 0.0141 mol MgSO4 = 7
Therefore, the value of x is 7.
Answer: a) The
of acetic acid at
is 
b) The percent dissociation for the solution is 
Explanation:

cM 0 0

So dissociation constant will be:

Give c= 0.10 M and
= ?
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![[H^+]=1.35\times 10^{-3}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1.35%5Ctimes%2010%5E%7B-3%7DM)
![[CH_3COO^-]=1.35\times 10^{-3}M](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D%3D1.35%5Ctimes%2010%5E%7B-3%7DM)
![[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M](https://tex.z-dn.net/?f=%5BCH_3COOH%5D%3D%280.10M-1.35%5Ctimes%2010%5E%7B-3%7D%3D0.09806M)
Putting in the values we get:


b) 



The three steps involve;
Step 1: Separation/expansion of the solute particles
Step 2: Separation/expansion of the solvent particles
Step 3; Combining the solute and solvent particles
The first two steps are usually endothermic. Step 3, nonetheless, can be either exothermic or endothermic and is significant in determining whether the dissolving process will be endothermic or exothermic.