N2 + 3H2 → 2NH3 △H = -92 kJ / mol
1 answer:
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Answer : The specific heat of the metal is,
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water =
= mass of metal = 97 g
= mass of water = 122 g
= final temperature of mixture =
= initial temperature of metal =
= initial temperature of water =
Now put all the given values in the above formula, we get
Therefore, the specific heat of the metal is,