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erastovalidia [21]
3 years ago
5

Why do we use moles when calculating empirical chemical formulas, but not the mass?

Chemistry
2 answers:
Arada [10]3 years ago
8 0

Answer:

because moles is the chemical unit*Avogadro's number, meaning it's the amount of atoms in the given unit.

Explanation:

MrMuchimi3 years ago
8 0
Because it’s the amount of atoms in the unit
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How many anions are in 0.500 g of MgBr2
Oksana_A [137]

<u>Given:</u>

Mass of MgBr2 = 0.500 g

<u>To determine:</u>

Number of anions in 0.500 g MgBr2

<u>Explanation:</u>

Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol

Moles of MgBr2 = 0.500 g/184 g.mol-1 = 0.00271 moles

Based on stoichiometry-

1 mole of MgBr2 has 1 mole of Mg2+ cations and 2 moles of Br- anions

Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-

Now,

1 mole of Br- contains 6.023 * 10²³ anions

0.00542 moles of Br- contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions

Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2


4 0
3 years ago
What is the total pressure (in atm) inside of a vessel containing N2 exerting a partial pressure of 0.256 atm, He exerting a par
Bezzdna [24]

Answer: Total pressure inside of a vessel is 0.908 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual partial pressures. exerted by each gas alone.

p_{total}=p_1+p_2+p_3

p_{N_2} = partial pressure of nitrogen = 0.256 atm

p_{He} = partial pressure of helium = 203 mm Hg = 0.267 atm  (760mmHg=1atm)

p_{H_2} = partial pressure of hydrogen =39.0 kPa = 0.385 atm  (1kPa=0.00987 atm)

Thus p_{total}=p_{H_2}+p_{He}+p_{H_2}

p_{total} =0.256atm+0.267atm+0.385atm =0.908atm

Thus total pressure (in atm) inside of a vessel is 0.908

8 0
3 years ago
Read 2 more answers
Some chemical reactions can proceed in just one direction . True or False ?
ss7ja [257]
The answer is False. i think
4 0
3 years ago
Read 2 more answers
A buffer is prepared containing 0.75 M NH3 and 0.20 M NH4 . Calculate the pH of the buffer using the Kb for NH3. g
denis-greek [22]

Answer:

pH=8.676

Explanation:

Given:

0.75 M NH_{3}

0.20 M NH_{4}

The objective is to calculate the pH of the buffer using the kb for NH_3

Formula used:

pOH=pka+log\frac{[salt]}{[base]}\\

pH=14-pOH

Solution:

On substituting salt=0.75 and base=0.20 in the formula

pOH=-log(1.77*10^{-5})+log\frac{0.75}{0.20}\\        =4.75+0.5740\\        =5.324

pH=14-pOH

On substituting the pOH value in the above expression,

pH=14-5.324

Therefore,

pH=8.676

3 0
3 years ago
Name and define the quantity represented by H​
Evgesh-ka [11]

Answer:

Molar enthalpy change, the enthalpy change for one mole of a pure substance

Explanation: i think

4 0
2 years ago
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