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Aleksandr [31]
3 years ago
14

Question 3

Physics
1 answer:
pickupchik [31]3 years ago
4 0
When a police officer is trying to decide if a driver is speeding, what is his point of reference. The speed limit
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force = mass x acceleration mass = force / acceleration acceleration = force / mass A 20 kg bike is moving at of 11 m/s². What f
earnstyle [38]

Answer:

220 N is the force

Explanation:

F=m x a

4 0
3 years ago
A ball is launched from a slingshot. As the ball travels along its trajectory, what force(s) are acting on it? Select all that a
ZanzabumX [31]

Force of air and gravitational force are acting on the ball when launched from the slingshot.

When a ball is launched from a slingshot, during its travel force of air as well as gravitational force are acting on the ball because there is air which moves opposite to the motion of a ball whereas the force of gravity attracts the ball downward.

The force of air slows down the motion of the ball while on the other hand, the force of gravity brings the ball to the ground due to attraction. If these two forces are not present then the ball continues its motion forever so we can conclude that force of air and force of gravity are acting on the ball when launched from the slingshot.

Learn more: brainly.com/question/25533186

4 0
3 years ago
If a 50 kg person is running at a rate of 2 m/s, the person’s momentum is
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6 0
3 years ago
Read 2 more answers
A secret agent is locked in a room. He pushes against the door but cannot open it. Finally, he falls to the floor exhausted. Has
Vitek1552 [10]

Answer: There is not work done at the door because the door did not move.

Explanation:  Work is defined as the movement done by a force.

So if you move to apply a force F in an object and you move it a distance D, the work applied on the object is  

W = F*D

In this case, the secret agent pushes against the door, so there is a force, but the agent does not move the door, so D = 0, so there is no motion of the door, which implies that there is no work done at the door.

8 0
3 years ago
A 25 {\rm pF} parallel-plate capacitor with an air gap between the plates is connected to a 100 {\rm V} battery. A Teflon slab i
jonny [76]

Answer:

0.275 nF

Explanation:

First of all, let's calculate the initial charge stored by the capactiro when it is in air. This is given by:

Q_0 = C_0 V

where

C_0 = 25 pF=25\cdot 10^{-12} F is the initial capacitance of the capacitor

V=100 V is the voltage of the battery

Substituting, we find

Q_0 = (25\cdot 10^{-12}F)(100 V)=25\cdot 10^{-10} F=0.25 nF

When the Teflon slab is inserted between the plates, the capacitance changes according to:

C'=kC_0

where

k=2.1 is the dielectric constant of Teflon. Therefore, the new charge stored on the capacitor will be:

Q'=C' V=(kC_0)V=(2.1)(25\cdot 10^{-12} F)(100 V)=0.525 nF

And so, the change in the charge on the capacitor is:

\Delta Q=Q'-Q=0.525 nF-0.25 nF=0.275 nF

7 0
3 years ago
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