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2 years ago

Question 3

Physics

1 answer:

pickupchik [31]2 years ago

4 0

When a police officer is trying to decide if a driver is speeding, what is his point of reference. The speed limit

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If the mass of a material is 47 grams and the volume of the material is 15 cm^3, what would the density of the material be?

uranmaximum [27]

Density is calculated as mass per unit volume. In this case, since the material has a mass of 47 grams and we have the volume of 15 cm^3, we can simply divide the values:
Density = 47 grams / 15 cm^3 = 3.1 g/cm^3
Therefore, the material has a density of 3.1 g/cm^3

8 0

3 years ago

A body of mass m, = 0.050 kg and initial velocity v₁ = 9 m / s turned to the right collides with a body of mass m₂ = 0.030 g wit

Ugo [173]

Answer:

Suppose two objects of different masses are moving with different velocities in the same direction on a straght-line before collision. After collision, they stick together and move with common (the same) velocity

6 0

2 years ago

A distance of 200 ft must be taped in a manner to ensure a standard deviation smaller than ± 0.04 ft. What must be the standard

Nutka1998 [239]

Answer:

The error in tapping is ±0.02828 ft.

Explanation:

Given that,

Distance = 200 ft

Standard deviation = ±0.04 ft

Length = 100 ft

We need to calculate the number of observation

Using formula of number of observation

$n=\dfrac{\text{total distance}}{\text{deviation per tape length}}$

Put the value into the formula

$n=\dfrac{200}{100}$

$n=2$

We need to calculate the error in tapping

Using formula of error

$E_{series}=\pm E\sqrt{n}$

$E=\dfrac{E_{series}}{\sqrt{n}}$

Put the value into the formula

$E=\dfrac{0.04}{\sqrt{2}}$

$E=\pm 0.02828\ ft$

Hence, The error in tapping is ±0.02828 ft.

3 0

3 years ago

An ideal gas is brought through an isothermal compression process. The 3.00 mol 3.00 mol of gas goes from an initial volume of 2

ozzi

Answer:

The answers can be found by considering the isothermal expansion equation as well as the ideal gas equation from where we have

The temperature T = 602.64K and the final pressure P = 110.24MPa

Explanation:

Numbeer of moles of gas = 3.00 mol

initial volume = 230.8×10−6 m3

final volume = 133.4×10−6 m3 .

released energy = 8240 J

Temperature = Constant = T

Pressure = $p_{f}$ =unknown

From the relation the combined ideal gas law, PV = nRT

Where R = 8.314 4621.JK−1mol−1

we have The release energy from compression P1V1 -P2V2

-qrev = -nRTln( $\frac{V_{2} }{V_{1} }$ ) = 8240J

n = 3

Hence -nRTln( $\frac{V_{2} }{V_{1} }$ ) = 3×8.314 462×ln $(\frac{133.4}{230.8})$ × T= -8240 J

or -13.67×T = -8240J, thus T = -8240/-13.67 = 602.64K

The Final pressure is given by

PV = n×R×T from where we have V = final volume thus

P = (n×R×T)/V = (3×8.134×602.64)÷(133.4× $10^{-6}$ ) = 110237041.1 N/ $m^{2}$ = 110.237MPa

8 0

3 years ago

X-ray diffraction is used to study the structure of crystallized proteins, nucleic acids, and other biological macromolecules. I

stepladder [879]

Answer:

PART A: option b. .43nm

PART B: option d. 0.11nm

PART C: option c. The wavelengths of visible light are too long compared to the atomic spacing.

Explanation:

Given data

Wavelength λ = 0.20 nm

Angle θ = 0.8 rad

(a)

wavelength of x-ray to give maximum at the same location

λ₂ = m λ

Here, m = 2 is the interference fringe order.

Substitute the values in the above equation.

λ₂ = 2 × 0.2

= 0.4 nm

Hence, the wavelength of x-ray to give maximum at the same location is 0.4nm

(b)

The crystal plane separation is equal to d

The value of θ is equal to 0.8 rad.

Convert rad into degree as follows:

0.8 rad = $\frac{180^0}{\pi rad} (\frac{0.8rad}{1})$ = 144°/π = 45.86°

Solve for d, using equation (1) as follows:

2dsinθ = mλ

d = mλ / 2sinθ

d = (1) 0.17 / 2Sin45.86°

d = 0.17 / 1.9065

d = 0.089 nm

(c)

The visible light can not be used to study the structure of proteins because of the high wavelength of the visible light.

7 0

2 years ago