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Y_Kistochka [10]
3 years ago
6

3 1/2 divided 2 3/5 in its simplest form

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

9.1 is answer or 91/10 or 9 1/10

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Find the volume of the cone in cubic feet. Use 3.14 for it and round your answer to the nearest tenth.
kenny6666 [7]
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {5,790,806.5\:ft^3 }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ:</u></h3>

Here, we area provided a cone with:

  • Radius = 48m
  • Height = 68 m

We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft

<h3><u>Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙ</u><u>ⳑɑ</u><u>:</u></h3>

The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:

\quad\longrightarrow\quad \sf { V =\dfrac{1}{3}\pi r^2 h }

<u>Therefore</u><u>,</u><u> </u><u>Volume:</u>

\implies\quad \tt {V = \dfrac{1}{3}\pi r^2 h }

\implies\quad \tt { V =\dfrac{1}{3}\times 3.14 \times 48^2 \times 68 }

\implies\quad \tt { V =\dfrac{1}{\cancel{3}}\times 3.14\times \cancel{2304} \times 68}

\implies\quad \tt {V =3.14\times 768\times 68 }

\implies\quad \tt {V = 163,983.36}

\implies\quad \tt { V = 163,983.36 \times (3.2808)^3 \qquad\quad\bigg[ As, \: 1m = 3.2808ft\bigg]}

\implies\quad \tt {V = 163,983.36\times 35.30 }

\implies\quad\underline{\pmb{ \tt { V = 5,790,806.5 ft^3}}}

‎ㅤ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume </u><u>of </u><u>given </u><u>cone </u><u>is </u><u>5,790,806.5</u><u> </u><u>f</u><u>t</u><u>³</u><u>.</u>

3 0
3 years ago
Plz help me with this
Zolol [24]
Answer : 4 & 5
Explanation :
4x-5/8 >-10 + 3x |multiply by 8
4x-5> -80 + 24x. | minus 4x , add 80
-5+80 > 24x -4x
75> 20x. |divide by 20
3.75 > x

So x is greater than 3.75 therefore 4 and 5 are the answers
7 0
3 years ago
if f(x) = ax^6 + bx^4 + cx^3 where a,b, and c are integers, how many distinct rational zeros could f(x) have
natita [175]

You can rewrite your function as

f(x) = x^3(ax^3+bx+c)

This implies that

f(x)=0 \iff x^3=0\quad\lor\quad ax^3+bx+c=0

Now, we have x^3=0\iff x=0, so it counts as a solution.

On the other hand, depending on the coefficient a, b and c, the cubic equation

ax^2+bx+c=0

can have either one or three solutions.

So, we have the solution x=0, and then one or three solutions coming from the cubic part. The equation as a whole thus have either two or four solutions, depending on the coefficients.

8 0
4 years ago
Is 20 times 5/6 greater than or less then 20?
ANTONII [103]
Greater than 20 because 5×6=30 so it passed
5 0
3 years ago
Read 2 more answers
1.
Dima020 [189]
I would say B sorry if im wrong tho
3 0
3 years ago
Read 2 more answers
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