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3 years ago

mary says then pen for her horse is a acute right angle. is this possible? explain clearly and explain everthing

1 answer:

3 0

The acute right angle means, the right angle is an acute angle so therefor it is not possible, because it is an acute angle not a right angle. Hope this helps :)

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1) 130<br> 2) 25<br> 3) 50<br> 4) 60

pickupchik [31]

2x+5x+5=180 so x has to be 25

3 0

3 years ago

Write 124 in scientific notation.

Artemon [7]

Answer:

Step-by-step explanation:

Write 124 in scientific notation.

Then, in scientific notation, 124 is written as 1.24 × 102. Actually, converting between "regular" notation and scientific notation is even simpler than I just showed, because all you really need to do is count decimal places.

6 0

3 years ago

Read 2 more answers

8 There are a combined 33 students who play a spring sport of track or

Rzqust [24]

The number of students that are on the track team are 18.

The number of students that are on the baseball team are 15.

<h3>What are the linear equations that represent the question?</h3>

a + b = 33 equation 1

a - b = 3 equation 2

Where:

a = number of students that are on the track team
b = number of students that are on the baseball team

<h3>How many students that are on the baseball team?</h3>

Subtract equation 2 from equation 1

2b = 30

Divide both sides by 2

b = 30/2 = 15

<h3>How many students that are on the track team?</h3>

Subtract 15 from 33: 33 - 15 = 18

To learn more about simultaneous equations, please check: brainly.com/question/25875552

#SPJ1

8 0

2 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago

4c+6+2<br><br> if anyone can tell me the answer it would mean so much!

hodyreva [135]

Answer:

Just combine like terms

6+2=8

4c can’t be combines

so 4c+8

3 0

3 years ago

Read 2 more answers