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o-na [289]
4 years ago
14

Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.7 rad/s 2 has an angular velocity of 0 rad

/s and an angular position of 8.8 rad. What is the angular position of the wheel after 2.7 s? Answer in units of rad.
Physics
1 answer:
saw5 [17]4 years ago
5 0

Answer:

The angular position of the wheel after 2.7 seconds is θf= 11.35 rad.

Explanation:

θi= 8.8 rad

ωi= 0 rad/seg

α= 0.7 rad/seg²

θf= θi + ωi * t + α * t² / 2

θf= 11.35 rad

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MrRissso [65]

Answer:5 N

Explanation:

Given

A physics major is cooking breakfast when he notices that the frictional force between his steel spatula and his Teflon frying pan is only 0.200 N

And from tables of coefficient of Kinetic friction for Teflon is \nu _k=0.04

and Friction force is \nu N

where N is the normal reaction

N=\frac{0.200}{0.04}=5 N

6 0
4 years ago
What keeps an inflated balloon from falling down if you rub it against your hair and place it against a wall? 1. rubbing distort
Keith_Richards [23]
2 because when you are doing this it causes friction Which then cause the balloon to stick
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3 0
3 years ago
An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: f=-f

and we also know that the object is placed a distance of twice the focal length, so p=2f

So we can find q from the equation above

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

And the magnification of the image is given by

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

5 0
4 years ago
Read 2 more answers
How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

  • Initial Velocity of car = 44km / hr.
  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

  • v is final Velocity.
  • u is Initial velocity.
  • a is acceleration.
  • t is time taken.

Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

6 0
3 years ago
An object has 600J of kinetic energy from its motion and a speed of 10m/s. What is it's mass?
Gemiola [76]

Answer:

The mass is 12 kg

Explanation:

KE = \frac{1}{2} mv²

Substitute:

600 = \frac{1}{2} m(10)²

600 = \frac{1}{2} m 100

600 = 50m

m = \frac{600}{50}

m = 12

4 0
3 years ago
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