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Drupady [299]
3 years ago
13

In a chemical reaction, activation energy increases the __________ of the reactants. This outcome causes the particles to collid

e, which results in the __________ of new products.
first blank-
a-amount of chemical energy
b- number of particles
c- temperature

second blank-
a- breaking up
b-formation
c-reactions

Physics
2 answers:
atroni [7]3 years ago
4 0

The answer is;

first blank-

A

Second blank-

B


Activation energy raised the potential energy of reactants to begin a chemical reaction. This requires an initial input of energy into the reaction before the reaction can then proceed spontaneously. That delta G of the activation energy is usually positive. This activation energy destabilized the stable  bonds of the reactants so they can form new bonds. This results to a transition state that is a high-energy state.


Stolb23 [73]3 years ago
4 0

Answer:

The first answer is c- temperature

the second is b-formation

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julia-pushkina [17]
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6 0
4 years ago
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Newer aircraft jet catapult systems use magnets instead of steam. The launch still takes 1.19 seconds, but the acceleration is a
Westkost [7]

Answer:

33.6 m

Explanation:

Given:

v₀ = 0 m/s

a = 47.41 m/s²

t = 1.19 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²

Δx = 33.6 m

8 0
3 years ago
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
A student who weighs 550 N is wearing a backpack that weighs 80 N. The student is standing still on level ground. Give your answ
siniylev [52]

Answer:

Explanation:

a) The magnitude of the net force on the student = 0 N since the student is standing still on level ground and upward reaction force = downward force.

b) the magnitude of the contact force on the student by the backpack = 80 N since the student was backing the backpack

c) the magnitude of the contact force o the student by the ground = 550 N + 80 N = 630 N reactional force on the student

6 0
3 years ago
Students were discussing a problem in which the class was asked to find the acceleration of a cart rolling up and down an inclin
velikii [3]

Sasha is correct: No, the velocity is changing at the top so the acceleration cant be zero.

Explanation:

The acceleration of an object is equal to the rate of change in velocity of the object:

a=\frac{\Delta v}{\Delta t} (1)

where

\Delta v is the change in velocity

\Delta t is the time interval

For the cart on the ramp, as the cart reaches the top of the ramp, its velocity becomes temporarily zero:

v = 0

This is the origin of Malia's mistake.

However, this only lasts a moment; in reality, its velocity is changing, in particular its direction is changing (from upward to downward).

As we can see from eq.(1), a non-zero change in velocity implies a non-zero acceleration. Therefore, Sasha is right, since the cart has a non-zero acceleration.

Learn more about acceleration:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

4 0
4 years ago
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