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kaheart [24]
3 years ago
13

Enter your answer in the provided box.

Chemistry
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

V₂ = 50.93 L

Explanation:

Initial volume, V_1=43.1\ L

Initial temperature, T_1=24^{\circ} C=24+273=297\ K

Final temperature, T_2=78^{\circ} C=78+273=351\ K

We need to find the final volume of the gas. The relation between the volume and the temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L

So, the final volume of the gas is 50.93 L.

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Para la siguiente reacción química demuestre que cumple con la Ley de la Conservación de la Materia. Recuerde que debe justifica
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Answer:

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In summary, if we look closely at the reaction, we observe that the stoichiometric values are balanced in the reaction, therefore there is THE SAME AMOUNT OF REAGENTS AS PRODUCTS.

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Explanation:

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4 0
3 years ago
When heating test tubes, always slant them away from yourself and others.<br> True<br> False
Leni [432]

Answer:

true

Explanation:

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3 years ago
Precision Problems:
Lorico [155]

Answer:

Precision = 2.70 \± 0.1\ cm

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm

Mean = \frac{18.9}{7}\ cm

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Step 2: Get The Range

Range = Highest - Lowest

Range = 2.80cm - 2.60cm

Range = 0.2\ cm

Step 3: Divide Range by 2

Approximate\ Range = \frac{1}{2}Range

Approximate\ Range = \frac{1}{2} * 0.2\ cm

Approximate\ Range = 0.1\ cm

Step 4: Determine the Precision

Precision = Average \± Approximate\ Range

Substitute 2.70 for Average and 0.1 for Approximate Range

Precision = 2.70 \± 0.1\ cm

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Hope this answer will help you.

6 0
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