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Answer : The mass of liquid sodium needed are, 
Explanation :
First we have to calculate the number of moles of liquid sodium.

where,
q = heat absorb = 1.20 MJ = 1.20 × 10⁶ J
n = number of moles of liquid sodium = ?
c = specific heat capacity = 
= change in temperature = 
Now put all the given values in the above formula, we get:


Now we have to calculate the mass of liquid sodium.
Molar mass of Na = 23 g/mol


Therefore, the mass of liquid sodium needed are, 
Answer:
Explanation:
In sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen .
In sulfur trioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen.
The ratio of oxygen which reacts with 32.06 gram of sulfur is 32: 48 .
This ratio is equal to 2 : 3.
This is in accordance with law of multiple proportion because , the ratio of mass of oxygen which reacts with constant mass of sulfur is integral ratio . Hence they are in accordance with law of multiple proportions.