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shusha [124]
3 years ago
7

Why has Earth's climate changed so rapidly in recent years?

Chemistry
1 answer:
ser-zykov [4K]3 years ago
5 0
I believe it’s C , People are burning too many fossil fuels .
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Convert 34.4 lb to g. (1 lb = 453.6 g) A) 7.58 X 10-2 g B) 1.56 X 103 g C) 7.58 X 104 g D) 1.56 X 102 g E) 1.56 X 104 g
Lesechka [4]

Answer:

E) 1.56x10⁴g

Explanation:

Pounds and grams are both units of mass. Pounds are used in UK and USA. Grams is the unit of mass used in the international system of units, SI.

To convert pounds, lb, to grams, g, we need the equivalence between these 2 units of mass:

1lb = 453.6g

That means 1lb weighs 453.6g. 34.4lb weigh:

34.4lb * (453.6g / 1lb) = 1.56x10⁴g. That means right option is:

<h3>E) 1.56x10⁴g</h3>
7 0
3 years ago
How many milliliters of a 20% solution should be added to 60 ml of a 40% solution to obtain a 35% solution?
weqwewe [10]
Add water to the sugar<span> and </span>pepper<span> and stir until the </span>sugar<span> is dissolved (</span>black pepper<span> will mix into the water but not dissolve.</span>
3 0
3 years ago
Calculate the formal charges of the atoms in co co2 and co32-
Dimas [21]
Every element in the compound has its own formal charge. The formula is:
Formal charge = Valence electrons - Nonbonding electrons - Bonding electrons/2
Let the Lewis structure of the compound aid you.

1. For CO:
Formal charge of C = 4 - 2 - 6/2 = -1
Formal charge of O = 6 - 2 - 6/2 = +1

2. For CO₂:
Formal charge of C = 4 - 0 - 8/2 = 0
Formal charge of each O = 6 - 4 - 4/2 = 0

3. For CO₃²⁻:
Formal charge of C: 4 - 0 - 8/2 = 0
Formal charge of two O's single-bonded to C = 6 - 6 - 2/2 = -1
Formal charge of the O double-bonded to C = 6 - 4 - 4/2 = 0

6 0
4 years ago
A 1000g Ni rod, heated to 150. °C was placed in 1.00 kg of water at 25.0 °C. The final temperature of the water was 26.3 °C. Wha
Shtirlitz [24]

Answer : The molar specific heat of Ni is, 2.576J/mole^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of Ni = ?

c_1 = specific heat of water = 4.18J/g^oC

m_1 = mass of Ni = 1000 g

m_2 = mass of water = 1 kg = 1000 g

T_f = final temperature of water = 26.3^oC

T_1 = initial temperature of Ni = 150^oC

T_2 = initial temperature of water = 25^oC

Now put all the given values in the above formula, we get

1000g\times c_1\times (26.3-150)^oC=-1000g\times 4.18J/g^oC\times (26.3-25)^oC

c_1=0.0439J/g^oC

Now we have to calculate the molar specific heat of Ni.

\text{Molar specific heat of Ni}=\text{Specific heat of Ni}\times \text{Molar mass of Ni}=(0.0439J/g^oC)\times (58.69g/mole)=2.576J/mole^oC

Therefore, the molar specific heat of Ni is, 2.576J/mole^oC

4 0
3 years ago
Is force a vector Yes or No ? Explain
Tcecarenko [31]

Answer:

YES

Explanation:

4 0
4 years ago
Read 2 more answers
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