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shusha [124]
3 years ago
7

Why has Earth's climate changed so rapidly in recent years?

Chemistry
1 answer:
ser-zykov [4K]3 years ago
5 0
I believe it’s C , People are burning too many fossil fuels .
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How do you calculate the volume of a cube? A. with a graduated cylindar in mL? B. with a triple beam balance in g? C. with a bea
Nuetrik [128]

Answer:

B

Explanation:

triple beam balance

sorry if i am wrong! can be brainliest?

5 0
3 years ago
A boy inflated a bunch of balloons while he was outside with an ambient temperature of 26oC. He then took the balloons inside hi
Strike441 [17]

Answer:

i think it would be 46C

Explanation:

3 0
3 years ago
1. In this experiment, the procedure instructs you to dissolve solid potassium hydrogen tartrate (KHT) in two different solvents
GuDViN [60]

Answer:

Water

Explanation:

Solid potassium hydrogen tartrates (KHT) is soluble in water. This is especially at room temperature.

The solvent for KHT is water.

3 0
3 years ago
The atomic mass of helium-4 is 4.0026 amu. How many of each
umka21 [38]

Answer:

Protons: 2.

Electrons: 2.

Neutrons: 2.

Explanation:

Hello,

In this case, since an atom's atomic number is equal to the number of electrons, considering the electron configurations, taking into account that helium-4 is neither positively nor negatively charged, we can infer that the number of electrons equal the number of protons, which in this case are 2, due to the fact that is atomic number is 2.

Moreover, as helium-4's atomic number is 4 as a whole number, we compute the number of neutrons by using the shown below equation:

Neutrons=mass\ number-atomic\ number\\\\Neutrons=4-2\\\\Neutrons=2

Regards.

7 0
3 years ago
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
 Zn =⇒ Zn+2(0.10) + 2e- (anode)
 Zn+2(?M) + 2e- === Zn(s) (cathode)
 
 Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn 
 E = E^o -0.0592 log Q; in this case E^o is zero. 
 E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2 
 23 mV x 1 volt/1000mv = 0.023 Volts 
 0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
 0.023 = -0.0296{ -1 - log[Zn+2] }
 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
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