a. Using the Clausius-Clapeyron equation
ln P1/P2 = (-Hvap / R) (1/T1 - 1/T2)
P1 = 197 mm Hg
P2 = 448 mm Hg
T1 = 23 C = 296 K
T2 = 45 C = 318 K
R = 8.314 J/mol-K
Solving for Hvap
Hvap = <span>29225.43 J/mol
b. For normal boiling point
</span>P1 = 197 mm Hg
P2 = 760 mm Hg (normal pressure)
T1 = 23 C = 296 K
T2 = ?
R = 8.314 J/mol-K
Hvap = 29225.43 J/mol
ln P1/P2 = (-Hvap / R) (1/T1 - 1/T2)
Use the equation to solve for T2
Answer: The average kinetic energy of water at
is
.
Explanation:
Given: Temperature = 
Kinetic energy is the energy acquired by the molecules of a substance due to its motion.
Formula to calculate average kinetic energy is as follows.

where,
T = temperature
k = Boltzmann constant = 
Substitute the value into above formula as follows.

Thus, we can conclude that the average kinetic energy of water at
is
.
Answer: gonna lin k answer key
6 ( tell me if you got it right)