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Viktor [21]
3 years ago
10

What is the (a) frequency and (b) wavelength (in nm) of a source of purple light at the edge of the visible light spectrum?

Chemistry
1 answer:
stiv31 [10]3 years ago
7 0

Answer: a) Frequency=666\times10^{12}Hz-789\times10^{12}Hz

b) Wavelength=380nm-450nm

Explanation: Visible light is a form of electromagnetic wave.

Wavelength is defined as the distance between two successive crests of a wave. It is represented as symbol \lambda.

Frequency is defined as the number of complete cycles happening per second. It is represented by the symbol \nu.

Wavelength and Frequency follow inverse relation,

                                              \nu=\frac{c}{\lambda}

where, c = speed of light = 3\times10^8m/s

Wavelength and frequency of a wave is usually expressed in a range.

a)  \text{Frequency of visible light}=666\times10^{12}Hz-789\times10^{12}Hz

b) \text{Wavelength of visible light}=380nm-450nm


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2 years ago
Tentukan pH Mg(OH)2 jika ke dalam larutan MgCl2 0,2M ditambahkan NH4OH sehingga
Vadim26 [7]

Answer:

pH 8.89

Explanation:

English Translation

If the MgCl₂ solution of 0.2 M has its pH raised by adding NH₄OH, the precipitate will begin to form at a pH of approximately.

Given the solubility product (Ksp) of Mg(OH)₂ = 1.2 x 10⁻¹¹

Assuming all of the salts involved all ionize completely

MgCl₂ ionizes to give Mg²⁺ and Cl⁻

MgCl₂ ⇌ Mg²⁺ + 2Cl⁻

1 mole of MgCl₂ gives 1 moles of Mg²⁺

Since the concentration of Mg²⁺ is the same as that of MgCl₂ = 0.2 M

Mg(OH)₂ is formed from 1 stoichiometric mole of Mg²⁺ and 2 stoichiometric moles of OH⁻

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[OH⁻]² = (6×10⁻¹¹)

[OH⁻] = √(6×10⁻¹¹)

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