-3(x + 5) = -9
-3x + -15 = -9
-3x - 15 = -9
-3x - 15 + 15 = -9 + 15 (we added 15 to both sides of the equation because now, the 15 on the left side cancels out).
-3x = 6
-3x/-3 = 6/-3
X = -2
So, in conclusion, X is equal to -2.
1. Let's call the number of carter school: "x" and "y" the number of alternative school. Then, you have that:
- T<span>he number of charter schools is 4 less than twice the number of alternative schools.
</span> - T<span>here are 48 charter schools in the country.
2. So, you have:
x=2y-4 (i)
x=48 (ii)
3. Then, when you substitute x=48 into the equation (i), you obtain:
</span>
x=2y-4
<span> 48=2y-4
4. Now, you must clear "y, as below:
48+4=2y
2y=52
y=52/2
y=26
</span><span>
How many alternative schools are in the county?
</span><span>
The answer is: There are 26 alternative schools.</span>

=

equals
k = 15.6
First, simplify

to 1.2. Your problem should look like:

= 1.2
Second, multiply both sides by 13. Your problem should look like: k = 15.6, which is the answer.
Answer: There are 1800 unique names from both the lists.
Explanation:
Since we have given that
there are two lists :
In First list, number of names = 1200
In Second list, number of names = 900
According to question , we have also given that
there are 150 names that appear on both lists,
So,
Number of unique names in the first list is given by

Number of unique names in the second list is given by

Therefore, total number of unique names is given by

Hence, there are 1800 unique names from both the lists.