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3 years ago

List 3 specific things you can do with a screw gun (not just screw in screws)

Engineering

1 answer:

alexandr402 [8]3 years ago

8 0

Answer:

1: Attaching a fork and wip eggs/batter/ ect.

2: You can entertain a cat by putting yarn on the gun/drill

3: If you get yarn everywere, you can spin the yarn up on the drill/gun

Explanation:

I hope this helps you out somehow

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Use the predicate specifications(x, y): x beats yF (x): x is an (American) football teamQ(x, y): x is quarterback of yL(x,y): x

attashe74 [19]

Answer:

a) ∀y∃x(Q(x, y))

b) (B(Jayhawks, W ildcats)→¬∀y(L(Jayhawks, y)))

c) ∃x(B(Wildcats, x) ∧ B(x, Jayhawks))

Explanation:

a) The statement can be rewritten as "For all football teams, there exists a quarterback" which is written in logical symbols.

b) The statement is an implication and thus have a premise and a conclusion. The premise states "Jayhawks beat the Wildcats" which is translated using B(x, y). The conclusion can be rewritten as "It is not the case that Jayhawks lose to all football teams".

c) The statement is a simple conjunction which can be written as "There exists a team x such that the Wildcats beats x and x beats Jayhawks"

7 0

3 years ago

An ant starts at one edge of a long strip of paper that is 34.2 cm wide. She travels at 1.3 cm/s at an angle of 61◦ with the lon

ankoles [38]

Answer:

t = 30.1 sec

Explanation:

If the ant is moving at a constant speed, the velocity vector will have the same magnitude at any point, and can be decomposed in two vectors, along directions perpendicular each other.

If we choose these directions coincident with the long edge of the paper, and the other perpendicular to it, the components of the velocity vector, along these axes, can be calculated as the projections of this vector along these axes.

We are only interested in the component of the velocity across the paper, that can be calculated as follows:

vₓ = v* sin θ, where v is the magnitude of the velocity, and θ the angle that forms v with the long edge.

We know that v= 1.3 cm/s, and θ = 61º, so we can find vₓ as follows:

vₓ = 1.3 cm/s * sin 61º = 1.3 cm/s * 0.875 = 1.14 cm/s

Applying the definition of average velocity, we can solve for t:

t = $\frac{x}{vx}$ = $\frac{34.2 cm}{1.14 cm/s} =30.1 sec$

⇒ t = 30.1 sec

7 0

3 years ago

Suppose that the following eight jobs must be scheduled through a car repair facility (repair times are shown in days): Car Repa

Usimov [2.4K]

Answer:

The answer is "F".

Hope this helped!

3 0

3 years ago

Moist air enters a duct at 10 oC, 70% relative humidity, and a volumetric flow rate of 150 m3/min. The mixture is heated as it f

AleksAgata [21]

70% of the chances you a car be a because if you see or 40° 51 5030 minutes and to 70% can be ignored to kinetic energy

7 0

3 years ago

A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli

lukranit [14]

Answer:

For the Top Side

- Strain ε = 0.00021739

- Elongation is 0.00260868 cm

For The Right side

- Strain ε = 0.00021739

-Elongation is 0.00347826 cm

Explanation:

Given the data in the question;

Length of the squared titanium plate = 12 cm by 12 cm = 0.12 m by 0.12 m

Thickness = 5 mm = 0.005 m

Force to the Top F $_t$ = 15 kN = 15000 Newton

Force to the right F $_r$ = 20 kN = 20000 Newton

elastic modulus, E = 115 GPa = 115 × 10⁹ pascal

Now, For the Top Side;

- Strain = σ/E = F $_t$ / AE

we substitute

= 15000 / ( 0.12 × 0.005 × (115 × 10⁹) )

= 15000 / 69000000

Strain ε = 0.00021739

- Elongation

Δl = ε × l

we substitute

Δl = 0.00021739 × 12 cm

Δl = 0.00260868 cm

Hence, Elongation is 0.00260868 cm

For The Right side

- Strain = σ/E = F $_r$ / AE

we substitute

Strain = 20000 / ( 0.12 × 0.005 × (115 × 10⁹) )

= 20000 / 69000000

Strain ε = 0.000289855

- Elongation

Δl = ε × l

we substitute

Δl = 0.000289855× 12 cm

Δl = 0.00347826 cm

Hence, Elongation is 0.00347826 cm

5 0

3 years ago