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Answer:
E= 15 GPa.
Explanation:
Given that
Length ,L = 0.5 m
Tensile stress ,σ = 10.2 MPa
Elongation ,ΔL = 0.34 mm
lets take young modulus = E
We know that strain ε given as
We know that
Therefore the young's modulus will be 15 GPa.
Answer:
Explanation:
Given
charge is placed at
another charge of is at
We know that Electric field due to positive charge is away from it and Electric field due to negative charge is towards it.
so net electric field is zero somewhere beyond negatively charged particle
Electric Field due to at some distance r from it
Now Electric Field due to is
Now
thus
Thus Electric field is zero at some distance r=1.43 cm right of