Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
Your answr is n=8. if this helped plz mark brainliest
Since we can find that the graphs Y value is by a factor of 2 looking at the graph we can find
f(3)=8
Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions 
and 
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction 
shown in purple, then we can plot the second one 
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.
The y intercept is 3
You can also say that the y intercept is at (0,3) which is a more detailed answer. However saying "y intercept is 3" is sufficient enough because the x coordinate of the y intercept is always x = 0.
The y intercept is the location where the graph crosses or touches the y axis. This is at the halfway point between the 2 and 4, so (2+4)/2 = 6/2 = 3
